Java：XML规范化 [英] Java: XML canonicalization

问题描述

在Java中制作规范形式的XML文件的最简单方法是什么？你有一些完成的代码吗？我在网上找到了几个链接，比如这个，这个，以及这个，但我无法让它工作：/

What's the easiest way to make a canonical form of a XML file in Java? Do you have some done code for that? I've found several links on the net, like this, this, and this, but I can't make it to work :/

谢谢，

Ivan

编辑：我使用了规范化程序那是在那里提出的，但我得到了奇怪的结果。为了更加精确，这种方法不会删除元素之间的空格......这就是我得到的：

I used the canonicalizer that was proposed down there, but I get strange results. To be more precize, this method doesn't delete white spaces between elements... This is what I get:

<Metric xmlns="http://www.ibm.com/wsla" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="total_memory_consumption_metric" type="double" unit="Mbit" xsi:schemaLocation="http://www.ibm.com/wsla WSLA.xsd">                        <Source>ServiceProvider</Source>                        <MeasurementDirective resultType="double" xsi:type="StatusRequest">                              <RequestURI> ***unused*** </RequestURI>                        </MeasurementDirective>                  </Metric>

推荐答案

Apache XML上的.apache.org / Java / api / org / apache / xml / security / c14n / Canonicalizer.html> Canonicalizer 课程安全项目：

The Canonicalizer class at Apache XML Security project:

Canonicalizer canon = Canonicalizer.getInstance(Canonicalizer.ALGO_ID_C14N_OMIT_COMMENTS);
byte canonXmlBytes[] = canon.canonicalize(yourXmlBytes);
String canonXmlString = new String(canonXmlBytes);

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