如何在JavaScript中获取两个对象数组之间的差异 [英] How to get the difference between two arrays of objects in JavaScript

问题描述

我有两个这样的结果集：

I have two result sets like this:

// Result 1
[
    { value="4a55eff3-1e0d-4a81-9105-3ddd7521d642", display="Jamsheer" },
    { value="644838b3-604d-4899-8b78-09e4799f586f", display="Muhammed" },
    { value="b6ee537a-375c-45bd-b9d4-4dd84a75041d", display="Ravi" },
    { value="e97339e1-939d-47ab-974c-1b68c9cfb536", display="Ajmal" },
    { value="a63a6f77-c637-454e-abf2-dfb9b543af6c", display="Ryan" }
]

// Result 2
[
    { value="4a55eff3-1e0d-4a81-9105-3ddd7521d642", display="Jamsheer"},
    { value="644838b3-604d-4899-8b78-09e4799f586f", display="Muhammed"},
    { value="b6ee537a-375c-45bd-b9d4-4dd84a75041d", display="Ravi"},
    { value="e97339e1-939d-47ab-974c-1b68c9cfb536", display="Ajmal"}
]

我需要的最终结果是这些数组之间的差异 - 最终结果应该像这个：

The final result I need is the difference between these arrays – the final result should be like this:

[{ value="a63a6f77-c637-454e-abf2-dfb9b543af6c", display="Ryan" }]

是否可以做在JavaScript中这样的东西？

Is it possible to do something like this in JavaScript?

推荐答案

只使用原生JS，这样的东西会起作用：

Using only native JS, something like this will work:

a = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal"},  { value:"a63a6f77-c637-454e-abf2-dfb9b543af6c", display:"Ryan"}]
b = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer", $$hashKey:"008"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed", $$hashKey:"009"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi", $$hashKey:"00A"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal", $$hashKey:"00B"}]

function comparer(otherArray){
  return function(current){
    return otherArray.filter(function(other){
      return other.value == current.value && other.display == current.display
    }).length == 0;
  }
}

var onlyInA = a.filter(comparer(b));
var onlyInB = b.filter(comparer(a));

result = onlyInA.concat(onlyInB);

console.log(result);

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