如何在 JavaScript 中获取两个对象数组之间的差异 [英] How to get the difference between two arrays of objects in JavaScript

问题描述

我有两个这样的结果集:

I have two result sets like this:

// Result 1
[
    { value: "0", display: "Jamsheer" },
    { value: "1", display: "Muhammed" },
    { value: "2", display: "Ravi" },
    { value: "3", display: "Ajmal" },
    { value: "4", display: "Ryan" }
]

// Result 2
[
    { value: "0", display: "Jamsheer" },
    { value: "1", display: "Muhammed" },
    { value: "2", display: "Ravi" },
    { value: "3", display: "Ajmal" },
]

我需要的最终结果是这些数组之间的差异——最终结果应该是这样的:

The final result I need is the difference between these arrays – the final result should be like this:

[{ value: "4", display: "Ryan" }]

可以在 JavaScript 中做这样的事情吗?

Is it possible to do something like this in JavaScript?

推荐答案

只使用本机 JS，这样的事情就行了:

Using only native JS, something like this will work:

const a = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal"}, { value:"a63a6f77-c637-454e-abf2-dfb9b543af6c", display:"Ryan"}];
const b = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer", $$hashKey:"008"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed", $$hashKey:"009"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi", $$hashKey:"00A"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal", $$hashKey:"00B"}];

// A comparer used to determine if two entries are equal.
const isSameUser = (a, b) => a.value == b.value && a.display == b.display;

// Get items that only occur in the left array,
// using the compareFunction to determine equality.
const onlyInLeft = (left, right, compareFunction) => 
  left.filter(leftValue =>
    !right.some(rightValue => 
      compareFunction(leftValue, rightValue)));

const onlyInA = onlyInLeft(a, b, isSameUser);
const onlyInB = onlyInLeft(b, a, isSameUser);

const result = [...onlyInA, ...onlyInB];

console.log(result);

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