使用RegExp删除所有特殊字符 [英] Remove all special characters with RegExp

问题描述

我想要一个将从字符串中删除所有特殊字符的RegExp。我正在尝试这样的东西，但它在IE7中不起作用，虽然它适用于Firefox。

I would like a RegExp that will remove all special characters from a string. I am trying something like this but it doesn’t work in IE7, though it works in Firefox.

var specialChars = "!@#$^&%*()+=-[]\/{}|:<>?,.";

for (var i = 0; i < specialChars.length; i++) {
  stringToReplace = stringToReplace.replace(new RegExp("\\" + specialChars[i], "gi"), "");
}

RegExp的详细说明也会有所帮助。

A detailed description of the RegExp would be helpful as well.

推荐答案

var desired = stringToReplace.replace(/[^\w\s]/gi, '')

正如评论中提到的那样，作为白名单更容易做到这一点 - 替换角色您的安全列表中不是。

As was mentioned in the comments it's easier to do this as a whitelist - replace the characters which aren't in your safelist.

插入符号（ ^ ）字符是集合的否定[... ] ， gi 说全局和不区分大小写（后者有点多余，但我想提一下），本例中的安全列表是数字，单词字符，下划线（ \w ）和空格（ \s ）。

The caret (^) character is the negation of the set [...], gi say global and case-insensitive (the latter is a bit redundant but I wanted to mention it) and the safelist in this example is digits, word characters, underscores (\w) and whitespace (\s).

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