递归函数返回undefined [英] Recursive function returns undefined

问题描述

我有一个计算税收的功能。

I have a function which calculates taxes.

function taxes(tax, taxWage) 
{
    var minWage = firstTier; //defined as a global variable
    if (taxWage > minWage) 
    {
        \\calculates tax recursively calling two other functions difference() and taxStep() 
        tax = tax + difference(taxWage) * taxStep(taxWage);
        var newSalary = taxWage - difference(taxWage);
        taxes(tax, newSalary); 
    }
    else 
    {
        returnTax = tax + taxWage * taxStep(taxWage);
        return returnTax;
    }
} 

我看不出它为什么不停止递归。

I can't see why it doesn't stop the recursion.

推荐答案

在你的职能部门：

if (taxWage > minWage) {
    // calculates tax recursively calling two other functions difference() and taxStep() 
    tax = tax + difference(taxWage) * taxStep(taxWage);
    var newSalary = taxWage - difference(taxWage);
    taxes(tax, newSalary); 
}

您没有从函数或设置中返回值 returnTax 。当你没有返回任何东西时，返回值是 undefined 。

you are not returning a value from the function or setting returnTax. When you don't return anything, the return value is undefined.

也许，你想要这个：

if (taxWage > minWage) {
    // calculates tax recursively calling two other functions difference() and taxStep() 
    tax = tax + difference(taxWage) * taxStep(taxWage);
    var newSalary = taxWage - difference(taxWage);
    return taxes(tax, newSalary); 
}

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