递归函数的javascript返回 [英] javascript return of recursive function

问题描述

讨厌为上一个问题的扩展开一个新问题:

Hate to open a new question for an extension to the previous one:

function ctest() {
    this.iteration = 0;
    this.func1 = function() {
        var result = func2.call(this, "haha");
        alert(this.iteration + ":" + result);
    }
    var func2 = function(sWord) {
        this.iteration++;
        sWord = sWord + "lol";
        if ( this.iteration < 5 ) {
            func2.call(this, sWord);
        } else {
            return sWord;
        }
    }
}

这将返回迭代 = 5 但结果未定义?这怎么可能?我明确返回 sWord.它应该返回hahalollollollollol"并且只是为了仔细检查，如果我在返回 sWord 之前警告(sWord)它会正确显示它.

this returns iteration = 5 but result UNDEFINED ? how is that possible ? i explicitly return sWord. It should have returned "hahalollollollollol" and just for doublecheck, if i alert(sWord) just before the return sWord it displays it correctly.

推荐答案

你必须一路返回栈顶:

func2.call(this, sWord);

应该是:

return func2.call(this, sWord);

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