在JavaScript中的岩石，纸，剪刀 [英] Rock, Paper, Scissors in JavaScript

问题描述

我正在制作我的第一个游戏（Rock Paper Sissors），当我遇到 userChoice 剪刀和 computerChoice <时，我遇到了一个问题/ strong>是摇滚，该计划无法将胜利者视为摇滚。我可以让程序给我任何其他组合的赢家。

I'm working on making my first game (Rock Paper Sissors) and I ran into an issue where when the userChoice is scissors and the computerChoice is rock, the program cannot return the winner as rock. I can get the program to give me the winner for any other combination.

我的代码在这里：

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
    computerChoice = "rock";
} else if(computerChoice <= 0.67) {
    computerChoice = "paper";
} else {
    computerChoice = "scissors";
}

var compare = function(choice1, choice2) {
    if(choice1 === choice2) {
    return "The result is a tie!";
}
if(choice1 === "rock") {
    if(choice2 === "scissors") {
        return "rock wins";
    } else {
        return "paper wins";
    }
}
if(choice1 === "paper") {
    if(choice2 === "rock") {
        return "paper wins";
    } else {
        if(choice2 === "scissors") {
            return "scissors wins";
    }
}
if(choice1 === "scissors") {
    if(choice2 === "rock") {
        return "rock wins";
    } else {
        if(choice2 === "paper") {
            return "scissors wins";
        }
    }
}
}
};
console.log("User Choice: " + userChoice);
console.log("Computer Choice: " + computerChoice);
compare(userChoice, computerChoice);

推荐答案

您无法看到最有可能发生的问题你的代码缩进不佳。正确缩进问题很清楚：

You were unable to see the issue most likely due to poor indentation of your code. Properly indented the issue is clear:

if (choice1 === "paper") {
    if (choice2 === "rock") {
        return "paper wins";
    } else {
        if (choice2 === "scissors") {
            return "scissors wins";
        }
    }
    if (choice1 === "scissors") {
        if (choice2 === "rock") {
            return "rock wins";
        } else {
            if (choice2 === "paper") {
                return "scissors wins";
            }
        }
    }
}

您的 if（choice1 ===scissors）{在之内if（choice1 ===paper）{ 。永远不会达到其中的代码。

Your if (choice1 === "scissors") { is within if (choice1 === "paper") {. The code within will never be reached.

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