在 java swing 中创建石头、纸、剪刀游戏的建议 [英] Advice for creating a rock, paper, scissors game in java swing

问题描述

我正在自学 Java，我想创建一个带有 GUI 的石头剪刀布游戏.我已经使用扫描仪创建了一个基于文本的版本，但我还有很多工作要做.

I'm teaching myself Java and I want to create a rock, paper, scissors game with a GUI. I have created a text based version with scanners, but I have a lot of work to go.

import javax.swing.JFrame;
import javax.swing.JPanel;

import javax.swing.JRadioButton;
import javax.swing.ButtonGroup;

public class RPS extends JFrame {

  JRadioButton rock, paper, scissors;
  ButtonGroup choices;

  public static void main(String[] args) {
    new RPS();
  }
  public RPS() {
    super("Rock, Paper, Scissors");

    setSize(400,300);
    setResizable(true);
    setDefaultCloseOperation(EXIT_ON_CLOSE);

    JPanel p=new JPanel();

    rock = new JRadioButton("Rock");
    paper = new JRadioButton("Paper");
    scissors = new JRadioButton("Scissors");

    choices = new ButtonGroup();
    choices.add(rock);
    choices.add(paper);
    choices.add(scissors);

    p.add(rock);
    p.add(paper);
    p.add(scissors);

    add(p);

    setVisible(true);
  }
}

这是我的代码.我已经让它创建了一个窗口并显示了 3 个单选按钮，这些按钮只允许选择一个选项.从这里开始，我想实现一个下一步按钮，并创建逻辑以根据两个选择生成答案.我相信我需要卡片布局，但 Oracle 文档对我没有帮助.我也不知道如何实现逻辑.任何帮助表示赞赏，抱歉长篇幅.再次感谢！

Here is my code. I already have it creating a window and displaying 3 radio buttons that will only allow one choice to be selected. From here, I want to implement a next button, and create logic to produce an answer based on both choices. I believe I need a card layout, but the Oracle documentation doesn't help me. I also have no idea how I can go around implementing logic. Any help is appreciated, sorry for the long post. Thanks again!

抱歉我没说清楚，我想设计这个让一个人轮流，按嵌套按钮，然后第二个人轮流，按完成并得到结果.我会把这个展示给我 8 年级的班级.

I'm sorry I didn't make it clear, I want to design this for one person to take a turn, press the nest button, then the second person will take a turn, press finish and get the results. I will present this to my 8th grade class.

推荐答案

这是在您的程序中实现 CardLayout 的热点.此布局的目的是对组件进行分层.在您的情况下，您需要为每个玩家设置一个面板.所以你需要两个面板.

Here's hot to implement CardLayout into your program. The purpose of this layout is to layer components. In your case, you would need a panel for each player. So you would need two panels.

1. 播放器 1 的 JPanel(带有三个单选按钮)
2. 播放器 2 的 JPanel(带有三个单选按钮)

以上两个是组成Card(layered)Layout(你可以将一个堆叠在另一个之上.

The above two are what comprise the Card(layered)Layout (you would stack one on top of the other.

1. 您需要一个标签来显示获胜者
2. 你需要一个 JPanel 来保存 Next Button

所以总的来说，你的布局应该是这样的

So all together, you layout should look like this

  Wrapped in JPanel(new BoderLayout())
-------------------------------------
|       label to show status        |   BorderLayout.NORTH
-------------------------------------
|                                   |
|        CardLayout holding         |
|        two JPanels with RBs       |   BorderLayout.CENTER
|___________________________________|
|(JPanel)   Next JButton            |   BorderLayout.SOUTH
-------------------------------------

点击next按钮时，可以调用CardLayout的next()方法显示下一个面板

When you click the next button, you can call the next() method of the CardLayout to show the next panel

示例

private CardLayout cardLayout = new CardLayout(10, 10); // hgap and vgap args
private JPanel cardPanel = new JPanel(cardLayout);

JPanel panel1 = new JPanel(); // holds first player
JPanel panel2 = new JPanel(); // holds second player

cardPanel.add(panel1);
cardPanel.add(panel2);

nextButton.addActionListener(new ActionListener(){
    public void actionPerformed(ActionEvent e){
        cardLayout.next(cardPanel);
    }
});

有关其他移动，请参阅 CardLayout 文档方法

See CardLayout docs for other movement methods

逻辑部分

1. 正如我之前建议的，你应该有六个单选按钮(每个玩家三个)
2. 在你的逻辑中，你可以检查哪些被选中
3. 并且您可能需要 checkWinner JButton 来执行操作.

示例

 JRadioButton p1Scissors = new JRadioButton("Scissors");
 JRadioButton p1Paper = new JRadioButton("Paper");
 JRadioButton p1Rock = new JRadioButton("Rock");
 // group them

 JRadioButton p2Scissors = new JRadioButton("Scissors");
 JRadioButton p2Paper = new JRadioButton("Paper");
 JRadioButton p2Rock = new JRadioButton("Rock");
 // group them

 JLabel statusLabel = new JLabel(" ");

 JButton checkWinner = new JButton("Check Winner"); // You can add to bottom panel

 checkWinner.addActionListener(new ActionListener(){
     public void actionPerformed(ActionEvent e){
         if (p1Scissors.isSelected() && p2Rock.isSelected()){
             statusLabel.setText("Player 2 wins: Rock beats Scissors");
         } else if ( ..... ) {
             ...
         }

         ...
     }
 });

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