匹配string中的所有URL并在JavaScript中返回数组 [英] Match all URLs in string and return in array in JavaScript
本文介绍了匹配string中的所有URL并在JavaScript中返回数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
例如,我有以下字符串:
For example, I have the following string:
var string = 'watch this video http://vimeo.com/8122132 and then see this picture http://www.flickr.com/photos/pmorgan/32606683/';
我希望找到所有有效的URL并将它们放在一个数组中,用JavaScript(和jQuery)完成),所以在这种情况下:
I wish to find all the valid URLs and place them in an array, done in JavaScript (and jQuery), so in this case:
url[0] = http://vimeo.com/8122132
url[1] = http://www.flickr.com/photos/pmorgan/32606683/
For现在,我只能匹配一个URL,但我想匹配所有。这就是我所拥有的:
For now, I can only match one URL, but I wish to match all. This is what I have:
geturl = new RegExp("(^|[ \t\r\n])((ftp|http|https|gopher|mailto|news|nntp|telnet|wais|file|prospero|aim|webcal):(([A-Za-z0-9$_.+!*(),;/?:@&~=-])|%[A-Fa-f0-9]{2}){2,}(#([a-zA-Z0-9][a-zA-Z0-9$_.+!*(),;/?:@&~=%-]*))?([A-Za-z0-9$_+!*();/?:~-]))");
var url = geturl.exec(string);
$('#urls').html(url[0]);
相信我,把url [1],url [2]等等不起作用: (
Trust me, putting url[1], url[2], etc. doesn't work :(
任何想法?
推荐答案
在Regexp中传递g
Pass "g" in Regexp
geturl = new RegExp(
"(^|[ \t\r\n])((ftp|http|https|gopher|mailto|news|nntp|telnet|wais|file|prospero|aim|webcal):(([A-Za-z0-9$_.+!*(),;/?:@&~=-])|%[A-Fa-f0-9]{2}){2,}(#([a-zA-Z0-9][a-zA-Z0-9$_.+!*(),;/?:@&~=%-]*))?([A-Za-z0-9$_+!*();/?:~-]))"
,"g"
);
string.match(geturl).length
2
string.match(geturl)
http://vimeo.com/8122132, http://www.flickr.com/photos/pmorgan/32606683/
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