将数字更改为int数组中的字母，并在Java中返回String [英] Change numbers to letters in a int array and return String in java

问题描述

我有一个 int数组(b [])，该数组具有随机长度和随机整数.我想将小于9的整数保留为整数，我想将数字 9-35 更改为字母 A-Z .我想在所有高于 35 的数字周围加上().因此 b [] = {1,10,36} 将生成一个 String 1A(36).我的尝试:

I have an int array (b[]) with a random length and random integers. I want to leave integers lower than 9 to how they are, i want to change the numbers 9-35 to letters A-Z. and i want do put () around all numbers higher than 35. So b[] = {1,10,36} would generate a String 1A(36). My try:

int b[] = {99, 2, 3, 4, 5, 10, 35, 24};  //sample input
char[] hilfsarray = new char[b.length];
char[] alphabet = "ABCDEFGHIJKLMNOPQRSTUVW".toCharArray();

for (int k = 0; k < hilfsarray.length; k++) //overwrite all positons with *
    hilfsarray[k] = '*';

for (int i = 0; i < b.length; i++) {
    int p = b[0] - 10;
    if (b[i] < 9 && b[i] <= 35) {
        hilfsarray[i] = alphabet[p];
    }
    return Arrays.toString(hilfsarray);
}

推荐答案

我认为这段代码可以完成您的工作.它使用Java-8，StreamAPI:

I think this code will do your job. It uses Java-8, StreamAPI:

public String someMethod() {
    int[] items = {99, 2, 3, 4, 5, 10, 35, 24}; // sample input
    String[] alphabet =
            "A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z".split(",");

    return Arrays.stream(items)
            .mapToObj(item -> (item > 9 && item <= 35) ?
                    alphabet[item - 10] : "(" + item + ")")
            .reduce("", String::concat);
}

样本输出:

(99)(2)(3)(4)(5)AZO

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