以相同的方式对两个数组排序 [英] Sort two arrays the same way

问题描述

例如，如果我有这些数组：

For example, if I have these arrays:

var name = ["Bob","Tom","Larry"];
var age =  ["10", "20", "30"];

我使用 name.sort（） name数组的顺序变为：

And I use name.sort() the order of the "name" array becomes:

var name = ["Bob","Larry","Tom"];

但是，如何对name数组进行排序并使age数组保持不变订购？像这样：

But, how can I sort the "name" array and have the "age" array keep the same order? Like this:

var name = ["Bob","Larry","Tom"];
var age =  ["10", "30", "20"];

推荐答案

您可以对现有数组进行排序，或重新组织数据。

You can sort the existing arrays, or reorganize the data.

方法1：
要使用现有数组，您可以对它们进行组合，排序和分离：
（假设等长数组）

var names = ["Bob","Tom","Larry"];
var ages =  ["10", "20", "30"];

//1) combine the arrays:
var list = [];
for (var j = 0; j < names.length; j++) 
    list.push({'name': names[j], 'age': ages[j]});

//2) sort:
list.sort(function(a, b) {
    return ((a.name < b.name) ? -1 : ((a.name == b.name) ? 0 : 1));
    //Sort could be modified to, for example, sort on the age 
    // if the name is the same.
});

//3) separate them back out:
for (var k = 0; k < list.length; k++) {
    names[k] = list[k].name;
    ages[k] = list[k].age;
}

这样做的好处是不依赖于字符串解析技术，可以使用在任何数量的需要一起排序的数组上。

This has the advantage of not relying on string parsing techniques, and could be used on any number of arrays that need to be sorted together.

方法2：或者您可以稍微重新组织数据，然后排序对象集合：

Method 2: Or you can reorganize the data a bit, and just sort a collection of objects:

var list = [
    {name: "Bob", age: 10}, 
    {name: "Tom", age: 20},
    {name: "Larry", age: 30}
    ];

list.sort(function(a, b) {
    return ((a.name < b.name) ? -1 : ((a.name == b.name) ? 0 : 1));
});

for (var i = 0; i<list.length; i++) {
    alert(list[i].name + ", " + list[i].age);
}
​

对于比较，-1表示较低的索引，0意味着相等，1意味着更高的指数。值得注意的是 sort（）实际上更改了基础数组。

For the comparisons,-1 means lower index, 0 means equal, and 1 means higher index. And it is worth noting that sort() actually changes the underlying array.

http://jsfiddle.net/ghBn7/38/

这篇关于以相同的方式对两个数组排序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！