以与另一数组JavaScript相同的方式对一个数组进行排序 [英] Sort one array the same way as another array JavaScript

问题描述

我有2个数组:

[2, 4, -2, 4, 1, 3]
["a", "b", "c", "d", "e", "f"]

并且我希望它们按数值数组排序:

and I want them to be sorted by the numerical array:

// output
[-2, 1, 2, 3, 4, 4] // <-sorted by numerical order
["c", "e", "a", "f", "b", "d"] // sorted exactly the same order as the first array

虽然"b"或"d"排在第一位实际上并不重要(在此示例中，它们都为4)

while its actually not important if "b" or "d" comes first (they both have 4 in this example)

我在网上发现了许多与此有关的问题，但是没有一个对我有用，谁能帮助我解决这个问题?

I found many questions about this online but none of them worked for me can anyone help me with that?

推荐答案

您可以对

You could sort the keys of the first array based on their value. This will return an array with indices of the array sorted based on the value of numbers array. Then use map to get the sorted values based on the indices

const numbers = [2, 4, -2, 4, 1, 3],
      alphabets = ["a", "b", "c", "d", "e", "f"]

const keys = Array.from(numbers.keys()).sort((a, b) => numbers[a] - numbers[b])

const sortedNumbers = keys.map(i => numbers[i]),
      sortedAlphabets = keys.map(i => alphabets[i])

console.log(
  sortedNumbers,
  sortedAlphabets
)

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