将资源用作类属性 [英] Using a Resource as a Class Property
问题描述
我想知道我是否正确这样做,只要使用另一个类
对象作为PHP类属性。
class my_baseclass {
var $ Database;
var $ ErrorMessage;
var $ TableName;
var $ RecordSet ;
函数my_baseclass(){
$ this-> TableName ="" ;;
$ this-> RecordSet = array ();
$ this-> Database = new my_database();
$ this-> ErrorMessage = $ this-> Database-> ErrorMessage;
返回true;
}
}
似乎工作正常,但是这种东西绕过我的PHP边缘
grok,所以我不知道。
I''m wondering if I''m doing this right, as far as using another class
object as a PHP class property.
class my_baseclass {
var $Database;
var $ErrorMessage;
var $TableName;
var $RecordSet;
function my_baseclass(){
$this->TableName = "";
$this->RecordSet = array();
$this->Database = new my_database();
$this->ErrorMessage = $this->Database->ErrorMessage;
return true;
}
}
It seems to be working, but this kinds stuff skirts the edge of my PHP
grok, so I dunno.
推荐答案
数据库;
var
Database;
var
ErrorMessage;
var
ErrorMessage;
var
TableName;
var
TableName;
var
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