无法在Python中将函数用作类属性 [英] Can't have a function as a class attribute in Python

问题描述

我想拥有一个普通的旧函数作为类常量。但是，Python对我来说有帮助地将其变成一种方法：

I want to have a plain old function as a class constant. However, Python "helpfully" turns it into a method for me:

class C(object):
    a = 17
    b = (lambda x : x+1)

print C.a     # Works fine for int attributes
print C.b     # Uh-oh... is a <unbound method C.<lambda>> now
print C.b(1)  # TypeError: unbound method <lambda>() must be called
              #    with C instance as first argument (got int instance instead)

• 有没有办法防止我的函数成为方法？


• 在任何情况下，解决此问题的最佳 Pythonic方法是什么？



推荐答案

静态方法：

class C(object):
    a = 17

    @staticmethod
    def b(x):
      return x+1

或：

class C(object):
    a = 17
    b = staticmethod(lambda x : x+1)

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