o / p问题 [英] o/p problem

问题描述

printf（"％d"，''++''）应该是什么;


ascii值为+是43 ...在turboC中输出为11051 ...（我感到惊讶的是它在编译时没有出错...）某人

解释我为如何输出...

what should be the ouptut of
printf("%d",''++'');

the ascii value of + is 43... the output comes as 11051 in turboC... (i
was surprised it doesnt throw an error on compiling... ) someone
explain me as to how this output comes...

推荐答案

2005年12月23日星期五04:33:33 -0800，fidlee写道：

On Fri, 23 Dec 2005 04:33:33 -0800, fidlee wrote:

应该是什么？
printf（"％d"，''++''）;

ascii值+是43 ...在turboC中输出为11051 ...
（我很惊讶它在编译时没有出错...）某人
解释我这个输出是怎么来的.. 。

what should be the ouptut of
printf("%d",''++'');

the ascii value of + is 43... the output comes as 11051 in turboC...
(i was surprised it doesnt throw an error on compiling... ) someone
explain me as to how this output comes...

6.4.4.4字符常数 ＃10：

包含多个

字符的整数字符常量的值（例如，''ab''），或包含<的字符或转义序列

不映射到单字节执行字符，

实现定义。


在你的情况下，43 * 256 + 43.


-

Pieter Droogendijk< pieter at binky dot org dot uk>

PGP / 1E92DBBC [Make皇帝最好的方式。 ] binky.org.uk

6.4.4.4 "Character constants" #10:
The value of an integer character constant containing more than one
character (e.g., ''ab''), or containing a character or escape sequence that
does not map to a single-byte execution character, is
implementation-defined.

In your case, 43 * 256 + 43.

--
Pieter Droogendijk <pieter at binky dot org dot uk>
PGP/1E92DBBC [ Make way for the Emperor''s Finest. ] binky.org.uk

fidlee写道：

什么应该是
printf的ouptut（" ％d，'''++''）;

+的ascii值是43 ...在turboC中输出为11051 ...（我很惊讶它没有在编译时抛出错误......）某人
解释我输出的结果......

what should be the ouptut of
printf("%d",''++'');

the ascii value of + is 43... the output comes as 11051 in turboC... (i
was surprised it doesnt throw an error on compiling... ) someone
explain me as to how this output comes...

字符常量可以包含多个字符，整数价值

是实施定义的。您需要查阅编译器附带的

文档以获取详细信息，但是您可以观察到43 * 256 + 43 = 11051这一事实。


Robert Gamble

Character constants can contain multiple characters, the integer value
of which is implementation-defined. You will need to consult the
documentation that came with your compiler for the details but you
might observe the fact that 43*256+43=11051.

Robert Gamble

@Robert


所以你的意思是说这个声明将在

不同的编译器上表现不同??

i也试过了

printf（"％d"，''+ a' ）;并且它给出11105 on g ++（linux）和turboC

（windows）我不认为他们是编译器依赖...


有人可以告诉我为什么编译器在

下面的行为？ （43 * 256 + 43 = 11051）

@ Robert

so u mean to say that this statement will behave differently on the
different compilers??
i also tried out
printf("%d",''+a''); and it gives 11105 on g++ (linux) and turboC
(windows) i dont think they are compiler dependednt...

Can someone please tell me as to why the compiler behaves in the
following way?? (43*256+43=11051)

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