解释以下程序的o / p。 [英] Explain the o/p of following program.

问题描述

解释以下程序的o / p.

  int  main（）
 {
  int  a [ 2 ] [ 3 ] = { 5 ， 10 ， 15 ， 20 ， 25 ， 30 }; 
  int （* p）[ 2 ] [ 3 ] =&安培;一个; 
 printf（ ％d \ t，***（p + 1） ）; 
 printf（ ％d \ t，*** p）; 
 printf（ ％d \ t，**（* p + 1） ）; 
} 

输出： -





垃圾，5,20;

解决方案

否。

我们不做你的作业：这是有原因的。它就是为了让你思考你被告知的事情，并试着理解它。它也在那里，以便您的导师可以识别您身体虚弱的区域，并将更多的注意力集中在补救措施上。



亲自尝试，你可能会发现它不是和你想的一样困难！



如果遇到具体问题，请询问相关问题，我们会尽力提供帮助。但我们不打算为你做这一切！



如果你无法使用调试器解决问题，那就在纸上做：写下来位置和地址并确切地查看所有内容应包含的内容。如果你仔细考虑一下发生的事情就很明显了。

正如我所说，这是一个功课;它不会在这里受理。

如果你希望我们做你的功课，那就不行了。这背后有一个很好的理由：你不会学到任何东西，如果你希望别人为你做你的工作。

我先读了这个：代码项目快速解答常见问题解答 [ ^ ]



-KR

Explain the o/p of following program.

int main()
{
    int a[2][3]={5,10,15,20,25,30};
    int (*p)[2][3]=&a;
    printf("%d\t",***(p+1));
    printf("%d\t",***p);
    printf("%d\t",**(*p+1));
}

OUTPUT:-


Garbage,5,20;

解决方案

No.
We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.

Try it yourself, you may find it is not as difficult as you think!

If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!

If you can't work it out using the debugger, then do it on paper: write down "locations" and "addresses" and see exactly what everything should contain. It's pretty obvious if you think a little about what is happening.

As I assume, this a homework; it won't entertained here.
If you expect us to do your homework, that's not going to work. There's a pretty good reason behind this: "You won't be learn anything, if you expect others do your work for you".
I'd read this first: Code Project Quick Answers FAQ[^]

-KR

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