一个C问题。 [英] A C Question.

问题描述

嗨：

有关C编程的问题：

只使用一个C语句检查变量是否为2的幂。否
$允许b $ b循环。

等待你的答案。我几天没有睡好了。

Hi:
There is question about C programming:
Use just one C statement to check whether a variable is the power of 2. No
loops allowed.
Waiting for your answer.I have not slept well a few days for this.

推荐答案

Jack Young写道：

Jack Young wrote:

嗨：
有关C编程的问题：
只使用一个C语句检查变量是否是2的幂。否
允许循环。
等待你的回答。我几天没睡好了。

Hi:
There is question about C programming:
Use just one C statement to check whether a variable is the power of 2. No
loops allowed.
Waiting for your answer.I have not slept well a few days for this.

int is_power_of_two（double x）{

返回x> 0.0; / *一个声明，没有循环* /

}


美梦！


-

Eric Sosman
es ***** @ acm-dot-org.inva lid

int is_power_of_two(double x) {
return x > 0.0; /* one statement, no loops */
}

Sweet dreams!

--
Eric Sosman
es*****@acm-dot-org.invalid

if（var％2 == 0）{

printf（" yep \ n"）;

}

if ( var % 2 == 0 ) {
printf("yep\n");
}

Jack Young写道：

Jack Young wrote:

嗨：
有关C编程的问题：
只使用一个C语句来检查一个变量是否是2的幂。不允许
循环。
等待你的答案。我几天没有睡好了。

Hi:
There is question about C programming:
Use just one C statement to check whether a variable is the power of 2. No
loops allowed.
Waiting for your answer.I have not slept well a few days for this.

puts（x&（x-1）|| x == 0？" not not power of two：power of two）;


Robert Gamble

puts(x & (x-1) || x==0 ? "not a power of two" : "power of two");

Robert Gamble

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