这合法吗？ [英] Is this legal?

问题描述

A级{

公开：

enum E {EN1，EN2，EN3};

};


B级{

public：

void f（const char * s，A :: E en = A :: E :: EN1）;

};


MSVC 7.1接受它，G ++ 3.2.2（3.2.2-3mdk）给出以下错误：

`A :: E''不是聚合类型


这是G ++或VC中的错误吗？神圣标准说什么？

class A {
public:
enum E { EN1, EN2, EN3 };
};

class B {
public:
void f(const char *s, A::E en = A::E::EN1);
};

MSVC 7.1 accepts it, G++ 3.2.2 (3.2.2-3mdk) gives the following error:
`A::E'' is not an aggregate type

Is this an error in G++ or in VC? What does the Holy Standard say?

推荐答案

red floyd写道：

red floyd wrote:

A类{
public：
enum E {EN1，EN2，EN3};
};

B班{
公开：
void f （const char * s，A :: E en = A :: E :: EN1）;
};

MSVC 7.1接受它，G ++ 3.2.2（3.2.2-3mdk ）给出以下错误：
`A :: E''不是聚合类型

这是G ++或VC中的错误吗？圣标说什么？

class A {
public:
enum E { EN1, EN2, EN3 };
};

class B {
public:
void f(const char *s, A::E en = A::E::EN1);
};

MSVC 7.1 accepts it, G++ 3.2.2 (3.2.2-3mdk) gives the following error:
`A::E'' is not an aggregate type

Is this an error in G++ or in VC? What does the Holy Standard say?

哎呀。错误是参考A :: E :: EN1默认参数值。

Oops. The error is in reference to the A::E::EN1 default parameter value.

red floyd写道：

red floyd wrote:

red floyd写道：

red floyd wrote:

A类{
公开：
枚举E {EN1，EN2，EN3};
};

B级{
公开：
void f（const char * s，A :: E en = A :: E :: EN1）;
};

`A :: E''不是聚合类型

这是一个G ++或VC中的错误？圣标说什么？

class A {
public:
enum E { EN1, EN2, EN3 };
};

class B {
public:
void f(const char *s, A::E en = A::E::EN1);
};

MSVC 7.1 accepts it, G++ 3.2.2 (3.2.2-3mdk) gives the following error:
`A::E'' is not an aggregate type

Is this an error in G++ or in VC? What does the Holy Standard say?

哎呀。错误是参考A :: E :: EN1默认参数值。

Oops. The error is in reference to the A::E::EN1 default parameter value.

枚举器是枚举类型相同范围内的名称

被宣布。即要进入EN1，你说A :: EN1，而不是A :: E :: EN1。


Victor

Enumerators are names in the same scope where the enumeration type
is declared. I.e. to get to EN1, you say A::EN1, not A::E::EN1.

Victor

Victor Bazarov写道：

Victor Bazarov wrote:

red floyd写道：

red floyd wrote:

[枚举范围问题编辑]

[enumeration scope question redacted]

枚举器是枚举类型
Victor

Enumerators are names in the same scope where the enumeration type
is declared. I.e. to get to EN1, you say A::EN1, not A::E::EN1.

Victor

谢谢，Victor。感谢帮助。

Thanks, Victor. Appreciate the help.

这篇关于这合法吗？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！