将db字段分配给具有动态构建的var名称的变量 [英] assign db fields to variables with dynamically built var names

查看:73
本文介绍了将db字段分配给具有动态构建的var名称的变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述




我需要将数据库数据存储在变量中,以便我可以使用它。

请在下面查看我在脚本中尝试做的事情....


如果你回复这些东西就行了。这意味着如果我回到$ row [''a5];我得到了我想要的数据,但我无法将数据存储在可维护的数据中。


我需要的东西从$ a1到$ a18,然后在每个商店中来自数据库名称a5中一个字段的数据。


谢谢


[PHP]

<? php

$ con = mysql_connect(" localhost"," *****"," ******");

if (!$ con)

{

die(''无法连接:''。mysql_error());

}


mysql_select_db(" *******",$ con);


$ result = mysql_query(" SELECT * FROM hole ORDER BY a5);


while($ row = mysql_fetch_array($ result))

{

$ a1 = $ row [''a5''];

$ a2 = $ row [''a5'']; ///////需要给出第二个结果

$ a3 = $ row [''a5'']; ///////需要给出第三个结果


}


echo"< img name = \" Hole \" SRC = \" $ a1.jpg\"宽度= \" 32\"高度= \" 32\" alt = \" Hole \">" ;;



mysql_close($ con);



?>

[/ PHP]

Hi,

I need to store database data in variables so I can work with it.
Please se below what I am trying to do in my script....

If you echo the stuff out is work fine. Meaning if I go echo $row[''a5]; I get the data I want but I can''t get the data to store in a vairable.

I need something that goes from $a1 to $a18 and in each of then store the data from one field in the database name a5.

Thanks

[PHP]
<?php
$con = mysql_connect("localhost","*****","******");
if (!$con)
{
die(''Could not connect: '' . mysql_error());
}

mysql_select_db("*******", $con);

$result = mysql_query("SELECT * FROM hole ORDER BY a5");

while($row = mysql_fetch_array($result))
{
$a1 = $row[''a5''];
$a2 = $row[''a5'']; /////// needs to give second result
$a3 = $row[''a5'']; /////// needs to give third result

}

echo "<img name=\"Hole\" src=\"$a1.jpg\" width=\"32\" height=\"32\" alt=\"Hole\">";



mysql_close($con);


?>
[/PHP]

推荐答案

row [''a5];我得到了我想要的数据,但是我无法将数据存储在可维护的数据中。


我需要的东西来自
row[''a5]; I get the data I want but I can''t get the data to store in a vairable.

I need something that goes from


a1到


a18然后在每个中存储数据库名称a5中的一个字段的数据。


谢谢


[PHP]

<?php
a18 and in each of then store the data from one field in the database name a5.

Thanks

[PHP]
<?php


这篇关于将db字段分配给具有动态构建的var名称的变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆