初始化结构 [英] initializing struct

问题描述

嗨！

我有一个很大的结构，我想立刻初始化它，但我得到解析

错误之前{"编译器错误。不能这样做吗？


#include< stdio.h>

#include< stdlib.h>


typedef struct {

int b;

int c;

int d;

int e;

} A;


A * a;


int main（void）{


a = malloc（4 * sizeof（* a））;

a = {1,1,4,5}; //来自我的编译器的错误

printf（"％d;％d \ nn，a-> b + a-> d，a-> c * a- > e）;


免费（一）;

返回0;

}


这是初个结构应该怎么做的坏方法？

解决方案

Carramba写道：

嗨！

我有一个大结构，我想立刻初始化它，但我得到解析

错误之前{"编译器错误。不能这样做吗？


#include< stdio.h>

#include< stdlib.h>


typedef struct {

int b;

int c;

int d;

int e;

} A;


A * a;


int main（void）{


a = malloc（4 * sizeof（* a））;

a = {1,1,4,5}; //我的编译器有错误

你不能为指针分配静态初始化器。你可以写


A a [4] = {{1}，{1}，{4}，{5}};


-

Ian Collins。

" Carramba" < ca ****** @ example.comschrieb im Newsbeitrag

新闻：f4 ********** @ aioe.org ...

嗨！

我有一个很大的结构，我想立刻初始化它，但我得到解析

不，你有一个指向结构的指针。

之前错误{"编译器错误。不能这样做吗？


#include< stdio.h>

#include< stdlib.h>


typedef struct {

int b;

int c;

int d;

int e;

} A;

这不是特别大......

>

A * a;

A b = {1,2,3,4};

int main（void） {


a = malloc（4 * sizeof（* a））;

a = {1,1,4,5}; //我的编译器有错误

删除这2行，替换为

A * a = b;
< blockquote class =post_quotes>
printf（"％d;％d \ n"，a-> b + a-> d，a-> c * a-> e）;


免费（一）;

返回0;

}


是这是init struct怎么做的坏方法？

只能作为定义的一部分，就像我上面所做的那样。而不是

指向struct的指针。


再见，Jojo

" Ian Collins" ; < ia ****** @ hotmail.comschrieb im Newsbeitrag

新闻：5d ************** @ mid.individual.net ...

Carramba写道：

>嗨！
我有一个很大的结构，我想要一次初始化它，但我在{之前得到解析
错误编译器错误。不能这样做吗？

#include< stdio.h>
#include< stdlib.h>

typedef struct {
int b;
int c;
int d;
int e;
} A;

A * a;

int main（void）{

a = malloc（4 * sizeof（* a））;
a = {1,1,4,5}; //我的编译器有错误

你不能为指针分配静态初始化器。你可以写


A a [4] = {{1}，{1}，{4}，{5}};

将[0] .b设置为1，将[1] .b设置为1，将[2] .b设置为4和a [3] .b到5，

留下所有c，d和e成员未初始化的resp。设置为0.


A a = {1,1,4,5};

会这样做......

再见，乔乔

Hi!
I have a big struct and I want to initialize it at once, but I get parse
error before "{" compiler error. can''t it by done?

#include <stdio.h>
#include <stdlib.h>

typedef struct{
int b;
int c;
int d;
int e;
}A;

A *a;

int main(void) {

a = malloc(4 * sizeof (*a));
a = {1,1,4,5}; //there is error from my compiler
printf("%d ; %d\n", a->b+a->d, a->c*a->e);

free(a);
return 0;
}

is this is bad way to init struct how one should do?

解决方案

Carramba wrote:

Hi!
I have a big struct and I want to initialize it at once, but I get parse
error before "{" compiler error. can''t it by done?

#include <stdio.h>
#include <stdlib.h>

typedef struct{
int b;
int c;
int d;
int e;
}A;

A *a;

int main(void) {

a = malloc(4 * sizeof (*a));
a = {1,1,4,5}; //there is error from my compiler

You can''t assign a static initialiser to a pointer. You could write

A a[4] = {{1},{1},{4},{5}};

--
Ian Collins.

"Carramba" <ca******@example.comschrieb im Newsbeitrag
news:f4**********@aioe.org...

Hi!
I have a big struct and I want to initialize it at once, but I get parse

No, you have a pointer to a struct.

error before "{" compiler error. can''t it by done?

#include <stdio.h>
#include <stdlib.h>

typedef struct{
int b;
int c;
int d;
int e;
}A;

That''s not particulary large...

>
A *a;

A b = {1,2,3,4};

int main(void) {

a = malloc(4 * sizeof (*a));
a = {1,1,4,5}; //there is error from my compiler

drop these 2 lines, replace by
A *a = b;

printf("%d ; %d\n", a->b+a->d, a->c*a->e);

free(a);
return 0;
}

is this is bad way to init struct how one should do?

Can be done only as part of the definition, like I did above. And not to a
pointer to struct.

Bye, Jojo

"Ian Collins" <ia******@hotmail.comschrieb im Newsbeitrag
news:5d**************@mid.individual.net...

Carramba wrote:

>Hi!
I have a big struct and I want to initialize it at once, but I get parse
error before "{" compiler error. can''t it by done?

#include <stdio.h>
#include <stdlib.h>

typedef struct{
int b;
int c;
int d;
int e;
}A;

A *a;

int main(void) {

a = malloc(4 * sizeof (*a));
a = {1,1,4,5}; //there is error from my compiler

You can''t assign a static initialiser to a pointer. You could write

A a[4] = {{1},{1},{4},{5}};

Which would set a[0].b to 1, a[1].b to 1, a[2].b to 4 and a[3].b to 5,
leaving all the c, d and e members uninitialized resp. set to 0.

A a = {1, 1, 4, 5};
Would do...
Bye, Jojo

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