如何初始化结构数组? [英] How to initialize array of structures with?

问题描述

struct SampleStruct {
   int a;
   int b;
   float c;
   double d;
   short e;       
};

对于这样的数组，我以前是这样初始化的:

For an array like this, I used to initialize it as below:

struct SampleStruct sStruct = {0};

我想知道当我声明这个结构的数组时，我认为这是正确的

I would like to know when I declare array of this structure, I thought this will be correct

struct SampleStruct sStructs[3] = {{0},{0},{0}};

但是，下面也被编译器接受了

But, below also got accepted by the compiler

struct SampleStruct sStructs[3] = {0};

我想知道最好、最安全的方法和详细原因.

I would like to know the best and safe way and detailed reason why so.

推荐答案

$ gcc --version
gcc (GCC) 4.6.1 20110819 (prerelease)

如果使用 -Wall 选项，我的 gcc 会给我关于第三个的警告:

If using -Wall option, my gcc gives me warnings about the third one:

try.c:11:9: warning: missing braces around initializer [-Wmissing-braces]
try.c:11:9: warning: (near initialization for ‘sStruct3[0]’) [-Wmissing-braces]

表示您应该编写 = {{0}} 进行初始化，这会将第一个结构的第一个字段设置为 0，其余所有字段都隐式设置为 0.程序在这个简单的情况下给出了正确的结果，但我认为你不应该依赖这个，需要正确地初始化.

indicating that you should write = {{0}} for initialization, which set the first field of the first struct to 0 and all the rest to 0 implicitly. The program gives correct result in this simple case, but I think you shouldn't rely on this and need to initialize things properly.

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