在C结构数组初始化 [英] struct array initialization in C

问题描述

下面是我的code的一部分。我想仅初始化 ArrayList的[0] 为 ArrayList的[0] .X = 0 和 ArrayList的[0] .Y = 0 。我并不需要初始化结构阵列的其余部分。我该怎么办呢？谢谢你。

 的#include＆LT;＆stdio.h中GT;
例如结构{
    INT X;
    诠释Ÿ;
};
例如结构数组列表[40];INT主（INT ARGC，CHAR *的argv []）{
    的printf（％d个\\ n％d个\\ N，ArrayList的[0] .X，ArrayList的[0] .Y）;
    返回0;
}
 

解决方案

您可以初始化结构数组的任何特定元素。

例如：

 结构ArrayList的例子[40] = {[0] = {0,0}}; //设置结构的第0个元素结构示例数组列表[40] = {[5] = {0,0}}; //设置结构的第6要素
 

这就是所谓指定初始化这曾经是一个GNU扩展C99之前将它改编并自C99还支持标准C。

Here is part of my code. I would like to initialize only the arraylist[0] as arraylist[0].x = 0 and arraylist[0].y = 0. I do not need to initialize the rest of the struct array. How can I do it? Thank you.

#include <stdio.h>
struct example {
    int x;
    int y;
};
struct example arraylist[40];

int main(int argc, char *argv[]){
    printf("%d\n %d\n", arraylist[0].x, arraylist[0].y);
    return 0;
}

解决方案

You can initialise any particular element of the struct array.

For example:

struct example arraylist[40] = { [0]={0,0}}; //sets 0th element of struct

struct example arraylist[40] = { [5]={0,0}}; //sets 6th element of struct

This is called Designated Initializers which used to be a GNU extension before C99 adapted it and is also supported in standard C since C99.

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