使用GCC / G ++输入typedef [英] Typedef with GCC/G++
问题描述
给出以下示例代码
typedef
struct fubar *
fubar;
struct fubar
{
};
int main（无效）
{
返回0;
}
Windows上的GCC会编译得很好，但是G ++会抛出错误说明
3：错误：''typedef struct fubar * fubar''的类型冲突$
2：错误：之前声明为''struct fubar''
6：错误：''struct fubar'的冲突类型''
3：错误：之前的声明为''typedef struct fubar * fubar''
现在我知道我可以通过简单地将结构重命名为
其他东西来避免这个错误，但我更愿意理解为什么这被解释为
不同。
Given the following example code
typedef
struct fubar *
fubar;
struct fubar
{
};
int main(void)
{
return 0;
}
GCC on Windows will compile this fine, but G++ throws an error saying
3: error: conflicting types for ''typedef struct fubar*fubar''
2: error: previous declaration as ''struct fubar''
6: error: conflicting types for ''struct fubar''
3: error: previous declaration as ''typedef struct fubar*fubar''
Now I know I can avoid this error by simply renaming the struct to
something else, but I''d prefer to understand why this is interpreted
differently.
推荐答案
2004年11月18日星期四21:46:54 -0800，Jeff Mott写道：
On Thu, 18 Nov 2004 21:46:54 -0800, Jeff Mott wrote:
考虑到这一点由于示例代码
typedef
struct fubar *
fubar;
struct fubar
}
int main（void）
{
返回0;
}
Windows上的GCC会编译得很好，但G ++会抛出错误说
3：错误：''typedef struct fubar * fubar''的冲突类型2：错误：上一个声明为''struct fubar''
6：错误：冲突的类型为''struct fubar''
3：错误：以前的声明为''typedef struct fubar * fubar''
现在我知道我可以通过简单地将结构重命名为其他的东西，但我更愿意理解为什么这个被解释不同。
Given the following example code
typedef
struct fubar *
fubar;
struct fubar
{
};
int main(void)
{
return 0;
}
GCC on Windows will compile this fine, but G++ throws an error saying
3: error: conflicting types for ''typedef struct fubar*fubar''
2: error: previous declaration as ''struct fubar''
6: error: conflicting types for ''struct fubar''
3: error: previous declaration as ''typedef struct fubar*fubar''
Now I know I can avoid this error by simply renaming the struct to
something else, but I''d prefer to understand why this is interpreted
differently.
好像你是故意问一个C ++问题C新闻组。
也许你应该尝试使用comp.lang.c ++而不是comp.lang.c.当然，首先要阅读他们的常见问题清单和/或章程（如果他们的b $ b有一个）可能是个好主意。
--Mac
Seems like you are knowingly asking a C++ question in a C newsgroup.
Maybe you should try comp.lang.c++ instead of comp.lang.c. It would
probably be a good idea to read their FAQ list and/or charter (if they
have one) first, of course.
--Mac
2004年11月18日星期五，Jeff Mott写道：
On Fri, 18 Nov 2004, Jeff Mott wrote:
给出以下示例代码
[snip] Windows上的GCC会编译得很好，但是G ++会抛出错误说
Given the following example code [snip] GCC on Windows will compile this fine, but G++ throws an error saying
不同的语言，不同的语法规则和不同的语义。
comp.lang.c ++在大厅里 - 问问那里，如果你真的想知道
为什么C ++会对待类名为类型，即使没有''struct''或''class''
标签附加。这个小组讨论了C，你的例子是完美的
有效C.
-Arthur
Different languages, different syntax rules and different semantics.
comp.lang.c++ is down the hall --- ask there, if you really want to know
why C++ treats class names as types even without the ''struct'' or ''class''
tag attached. This group discusses C, and your example is perfectly
valid C.
-Arthur
mj****@twcny.rr.com （Jeff Mott）写道：
mj****@twcny.rr.com (Jeff Mott) writes:
给定以下示例代码
typedef
struct fubar *
fubar;
struct fubar
{
};
int main（void）
{
返回0;
}
Windows上的GCC会编译得很好，但是G ++会抛出错误说
3：错误：''typedef struct fubar * fubar''的冲突类型2：错误：上一个声明为''struct fubar''
6：错误：冲突类型对于''struct fubar''
3：错误：以前的声明为''typedef struct fubar * fubar''
现在我知道我可以通过简单地将结构重命名为<来避免这个错误其他的东西，但我更愿意理解为什么这是inter不同的。
Given the following example code
typedef
struct fubar *
fubar;
struct fubar
{
};
int main(void)
{
return 0;
}
GCC on Windows will compile this fine, but G++ throws an error saying
3: error: conflicting types for ''typedef struct fubar*fubar''
2: error: previous declaration as ''struct fubar''
6: error: conflicting types for ''struct fubar''
3: error: previous declaration as ''typedef struct fubar*fubar''
Now I know I can avoid this error by simply renaming the struct to
something else, but I''d prefer to understand why this is interpreted
differently.
G ++是一个C ++编译器。尝试comp.lang.c ++（他们可能会告诉你/ b
，不像在C中，给出一个声明struct fubar {/ * ... * /}，
类型可以简称为fubar。
-
Keith Thompson（The_Other_Keith） ks *** @ mib.org < http://www.ghoti.net/~kst>
San迭戈超级计算机中心< *> < http://users.sdsc.edu/~kst>
我们必须做点什么。这是事情。因此，我们必须这样做。
G++ is a C++ compiler. Try comp.lang.c++ (where they''ll probably tell
you that, unlike in C, given a declaration "struct fubar { /* ... */}",
the type can be referred to as just "fubar").
--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
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