功能使用指针 [英] Function Using Pointers
问题描述
我有一个函数（我从你们其中一个人那里窃取了代码
在comp.lang.c中）：
void myStringClean（char *字符串）{
char *指针;
if（（pointer = strchr（String，''\ n''））！= NULL）{
*指针=''\ 0'';
}
}
我该怎么称呼这个功能？我在main.c中这样打过电话：
myStringClean（myName）;
我打电话时没有错误或警告
这样的功能
gcc -ansi -pedantic -Wall -W，
当我用它来调用它时
myStringClean（ & myName）;
我收到警告
从不兼容的指针类型传递''myStringClean'的arg 1。
mSC.h中的原型如下所示：
#include< string.h>
void myStringClean（char * String）;
提前感谢您的回复。
-
未找到匹配项
I have a function(whose code I have stolen from one of you
in comp.lang.c):
void myStringClean(char *String) {
char *pointer;
if((pointer = strchr(String, ''\n'')) != NULL) {
*pointer = ''\0'';
}
}
How should I call this function? I''ve called like this in main.c:
myStringClean(myName);
I get no errors or warnings when I call
the function like this with
gcc -ansi -pedantic -Wall -W,
when I call it using
myStringClean(&myName);
I get the warnings
passing arg 1 of ''myStringClean'' from incompatible pointer type.
The prototype in mSC.h looks like this:
#include <string.h>
void myStringClean(char *String);
In advance thanks for helpful replies.
--
No matches found
推荐答案
首先，如果您希望收到对您问题的回复，我建议您从新闻阅读器中删除''hannibalkannibalATyahooDOTno''
$ b'b配置为''Followup-To''字段。
周一，2004年1月5日15:43:09 -0500，Eirik WS写道：
First, if you would like to receive replys to your question, I
recommend removing ''hannibalkannibalATyahooDOTno'' from your news reader
configuration for the ''Followup-To'' field.
On Mon, 05 Jan 2004 15:43:09 -0500, Eirik WS wrote:
当我使用
myStringClean（& myName）调用它时;
我收到警告
从不兼容的指针传递''myStringClean'的arg 1类型。
when I call it using
myStringClean(&myName);
I get the warnings
passing arg 1 of ''myStringClean'' from incompatible pointer type.
myName的声明不是''char * myName;''。也许你正在使用
''char myName [N];''？
Mike
The declaration of myName is not ''char *myName;''. Perhaps you''re using
''char myName[N];''?
Mike
Eirik WS< hx ****************************** @ xyxaxhxoxox.no>这样说：
Eirik WS <hx******************************@xyxaxhxoxox.no > spoke thus:
void myStringClean（char * String）{
char * pointer;
if（（pointer = strchr（String，''\ n'） '））！= NULL）{
* pointer =''\''';
}
}
我该如何调用此函数？我在main.c中这样调用过：
myStringClean（myName）;
当我用
gcc -ansi调用
这个函数时我没有错误或警告-pedantic -Wall -W，
我这用来表示myName被声明为
char myName [512]; / *或者* /
当我用
myStringClean（& myName）调用它时;
我收到警告
传递''myStringClean'的arg 1 '来自不兼容的指针类型。
void myStringClean(char *String) {
char *pointer;
if((pointer = strchr(String, ''\n'')) != NULL) {
*pointer = ''\0'';
}
} How should I call this function? I''ve called like this in main.c: myStringClean(myName);
I get no errors or warnings when I call
the function like this with
gcc -ansi -pedantic -Wall -W,
I take this to indicate that myName is declared as
char myName[512]; /* or something */
when I call it using
myStringClean(&myName);
I get the warnings
passing arg 1 of ''myStringClean'' from incompatible pointer type.
如果我上面的评论是正确的，那么& myName确实是不兼容的
与你的声明myStringClean。 myStringClean将一个指针
作为参数接受一个字符。 myName是一个指向角色的指针，所以
你的第一次尝试工作正常。但是，& myName是指向一个字符的指针
，这不是同一个东西。感谢gcc for
请指出这一点。
-
Christopher Benson-Manica |我*应该*知道我在说什么 - 如果我
ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。
If my comment above is correct, then &myName is, indeed, incompatible
with your declaration of myStringClean. myStringClean takes a pointer
to a character as a parameter. myName is a pointer to a character, so
your first try works fine. &myName, though, is a pointer to a pointer
to a character, which is not the same thing. Say thank you to gcc for
kindly pointing this out to you.
--
Christopher Benson-Manica | I *should* know what I''m talking about - if I
ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.
Christopher Benson-Manica< at *** @ nospam.cyberspace.org>这样说：
Christopher Benson-Manica <at***@nospam.cyberspace.org> spoke thus:
char myName [512]; / *或者某些东西* /
如果我上面的评论是正确的，那么& myName确实与你的myStringClean声明不兼容。 myStringClean将一个指针
作为参数。 myName是一个指向角色的指针，所以
你的第一次尝试工作正常。但是，& myName是指向字符的指针，这不是同一个东西。感谢gcc for
请指出这一点。
char myName[512]; /* or something */ If my comment above is correct, then &myName is, indeed, incompatible
with your declaration of myStringClean. myStringClean takes a pointer
to a character as a parameter. myName is a pointer to a character, so
your first try works fine. &myName, though, is a pointer to a pointer
to a character, which is not the same thing. Say thank you to gcc for
kindly pointing this out to you.
嗯...我只想说我期待并欢迎关于<的评论事实上，我不明智地将myName称为指向角色的指针...
* doh *
-
Christopher Benson-Manica |我*应该*知道我在说什么 - 如果我
ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。
Um... let me just say that I expect and welcome comments about the
fact that I injudiciously called myName a pointer to a character...
*doh*
--
Christopher Benson-Manica | I *should* know what I''m talking about - if I
ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.
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