指针功能 [英] Pointers in function
问题描述
你好
如何将指针传递给函数并将其设置为指向特定的
地址？我正在尝试在这个简单的示例代码中执行此操作，但是这个
函数不会更改指针名为counter的地址。我知道我可以简单地改变这段代码来改变计数器的价值
变量，但我想要做的是真实的是设置指针
作为函数参数传递给指向类对象。我希望我写得很清楚。
我会很乐意为你提供帮助
int func（int * counter） {
int * pToInt = new int;
* pToInt = 5;
counter = pToInt;
return 0;
}
int main（int argc，char * argv []）
{
int *测试;
func（测试）;
coutu<< * test<< endl;
system（" Pause"）;
返回0;
}
Hello
How to pass pointer to function and set it to point on particular
address? I''m trying to do this in this simple&sample code, but this
function doesn''t change address pointed by pointer named counter. I
know that I can simple change this code to change value of the counter
variable, but what what I want to do for real is to set up pointer
passed as function argument to point on a class object. I hope I wrote
this quite clear.
I would be greatfull for your help
int func(int* counter){
int* pToInt=new int;
*pToInt=5;
counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(test);
coutu<<*test<<endl;
system("Pause");
return 0;
}
推荐答案
mangood2005写道：
mangood2005 wrote:
Hello
如何将指针传递给函数并将其设置为指向特定的地址？我正在尝试在这个简单的示例代码中执行此操作，但此功能不会更改指针名为counter的地址。我知道我可以简单地改变这段代码来改变计数器变量的值，但是我想要做的是真实的是设置指针
作为函数参数传递给指向一个类对象。我希望我写得很清楚。
我会非常感谢你的帮助
int func（int * counter）{
int * pToInt = new int;
* pToInt = 5;
counter = pToInt;
返回0;
}
int main（int argc，char * argv []）
{
int * test;
func（test）;
coutu<< * test<< endl;
system（" Pause"）;
返回0 ;
}
Hello
How to pass pointer to function and set it to point on particular
address? I''m trying to do this in this simple&sample code, but this
function doesn''t change address pointed by pointer named counter. I
know that I can simple change this code to change value of the counter
variable, but what what I want to do for real is to set up pointer
passed as function argument to point on a class object. I hope I wrote
this quite clear.
I would be greatfull for your help
int func(int* counter){
int* pToInt=new int;
*pToInt=5;
counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(test);
coutu<<*test<<endl;
system("Pause");
return 0;
}
你需要传递指针的地址：
int func （int ** counter）{
int * pToInt = new int;
* pToInt = 5;
* counter = pToInt;
返回0;
}
int main（int argc，char * argv []）
{
int * test;
func（& test）;
cout<< * test<< endl;
系统（暂停）;
返回0;
}
或者您可以使用参考：
int func（int * &安培;柜台）{
int * pToInt = new int;
* pToInt = 5;
counter = pToInt;
返回0;
}
int main（int argc，char * argv []）
{
int * test;
func（test）;
cout<< * test<< endl;
system（" Pause" ）;
返回0;
}
- Pete
You need to pass the address of the pointer:
int func(int** counter){
int* pToInt=new int;
*pToInt=5;
*counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(&test);
cout<<*test<<endl;
system("Pause");
return 0;
}
Or you can use references:
int func(int*& counter){
int* pToInt=new int;
*pToInt=5;
counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(test);
cout<<*test<<endl;
system("Pause");
return 0;
}
- Pete
Pete C.写道：
Pete C. wrote:
mangood2005写道：
mangood2005 wrote:
你好
如何将指针传递给函数并将其设置为指向特定的地址？我正在尝试在这个简单的示例代码中执行此操作，但此功能不会更改指针名为counter的地址。我知道我可以简单地改变这段代码来改变
计数器变量的值，但是我想要做的事情就是设置
指针作为函数参数传递给指向一个类对象。我希望我写得非常清楚。
我会很乐意为你提供帮助
int func（int * counter）{
int * pToInt = new int;
* pToInt = 5;
counter = pToInt;
返回0;
}
int main（int argc，char * argv []）
{
int * test;
func（test）;
coutu<< * test<< endl;
system（" Pause"）;
返回0 ;
}
Hello
How to pass pointer to function and set it to point on particular
address? I''m trying to do this in this simple&sample code, but this
function doesn''t change address pointed by pointer named counter. I
know that I can simple change this code to change value of the
counter variable, but what what I want to do for real is to set up
pointer passed as function argument to point on a class object. I
hope I wrote this quite clear.
I would be greatfull for your help
int func(int* counter){
int* pToInt=new int;
*pToInt=5;
counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(test);
coutu<<*test<<endl;
system("Pause");
return 0;
}
你需要传递指针的地址：
int func（int ** counter）{
int * pToInt = new int;
* pToInt = 5;
* counter = pToInt;
返回0;
}
int main（int argc， char * argv []）
{
int * test;
func（& test）;
cout<< * test<< endl;
system （暂停）;
返回0;
}
或者你可以使用引用：
int func（int * & counter）{
int * pToInt = new int;
* pToInt = 5;
counter = pToInt;
返回0;
}
int main（int argc，char * argv []）
{
int * test;
func（test）;
cout<< * test<< endl;
system（" Pause" ;）;
返回0;
}
- Pete
You need to pass the address of the pointer:
int func(int** counter){
int* pToInt=new int;
*pToInt=5;
*counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(&test);
cout<<*test<<endl;
system("Pause");
return 0;
}
Or you can use references:
int func(int*& counter){
int* pToInt=new int;
*pToInt=5;
counter=pToInt;
return 0;
}
int main(int argc, char* argv[])
{
int* test;
func(test);
cout<<*test<<endl;
system("Pause");
return 0;
}
- Pete
顺便说一句，你需要记住删除你的指针。每个新的必须有相应的删除，每个新的[]都必须删除[]。
- Pete
By the way, you need to remember to delete your pointer. Every new must have
a corresponding delete, every new[] must have a delete[].
- Pete
" Pete C." < x@x.x>在消息中写道
新闻：％k **************** @ newsread1.news.pas.earthli nk.net ...
"Pete C." <x@x.x> wrote in message
news:%k****************@newsread1.news.pas.earthli nk.net...
mangood2005写道：
你需要传递指针的地址：
int func（int ** counter）{
mangood2005 wrote:
You need to pass the address of the pointer:
int func(int** counter){
使用两个星号是什么意思？我有一个程序工作，传递
指针，其中参数是这样的，
（int * iscreenX）
和其他所有内容都与你的方式相同。你知道
有什么区别？我真的很好奇，在使用Java之后，我对C ++相对较新，但是我已经习惯了指针。
谢谢
Nick howes
What does it mean to use two asterisks? I have a program working that passes
pointers where the argument is like this,
(int *iscreenX)
and everything else is otherwise the same to how you did it. do you know
what the difference is? I''m just curious really, I''m relatively new to C++
after using Java but i''m getting used to pointers.
thanks
Nick howes
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