for循环没有停止它应该 [英] for loop not stopping when it should
问题描述
我正在检查并查看是否输入了数字以外的其他内容（+，
- ，*或/）一个文本框，其中bigR就是我所说的文本框中的文本。我可以得到输入的内容和字符串中的位置（
，其中部分是下面的第一部分）。我遇到麻烦只是
之后。我测试了breakpt [0]的值是多少，得到3，如果输入100 + 200那么它应该是
。但是当我运行j = 0到j
$时b $ b =< breakpt [0]，它不会停在2，但一直持续到索引结束
数组。
如果消息框说breakpt [0] = 3，为什么不止于2？
谢谢!!!
Melanie
int i，j;
for（i = 0; i< bigR.Length; i ++）
{
if（（bigR [i] ==' '+''）||（bigR [i] =='' - ''）||（bigR [i] ==''*''）||（bigR [i]
==''/''））
{breakpt + = i;}
}
// breakpt [0 ] = 3如果类型100 + 200
MessageBox.Show（breakpt [0] .ToString（））;
for（j = 0; j< ; breakpt [0]; j ++）
{
MessageBox.Show（j.ToString（））;
nums + = bigR [j ];
}
Hi,
I''m trying to check and see if something other than numbers (either the +,
-, *, or /) are entered into a textbox, where bigR is what I call the text in
the textbox. I can get what was entered and where along the string (the
where part is the first section of below). I''m running into trouble just
after that. I tested what the value of breakpt[0] and got 3, which it should
be if entering something like 100 + 200. But when I run the for j = 0 to j
= < breakpt[0], it doesn''t stop at 2, but keeps going until the index is out
of the array.
If the messagebox says breakpt[0] = 3, why doesn''t j stop at 2?
Thanks!!!
Melanie
int i, j;
for(i = 0; i < bigR.Length; i++)
{
if ((bigR[i] == ''+'') || (bigR[i] == ''-'') || (bigR[i] == ''*'') || (bigR[i]
== ''/''))
{breakpt += i;}
}
// breakpt[0] = 3 if type 100+200
MessageBox.Show(breakpt[0].ToString());
for (j = 0; j < breakpt[0]; j++)
{
MessageBox.Show(j.ToString());
nums += bigR[j];
}
推荐答案
melanieab写道：
melanieab wrote:
<我正在尝试检查并查看数字以外的其他内容（
+， - ，*或/）是否输入到文本框中，wh bigR是我在文本框中调用文本的内容。我可以得到输入的内容和字符串中的
（其中部分是下面的第一部分）。我刚刚在那之后遇到了麻烦。我测试了
breakpt [0]的值是什么，得到3，如果输入类似
100 + 200的话应该是。但是当我运行for j = 0到j =< breakpt [0]，它不会停在2，但一直持续到索引超出
数组。
如果消息框说breakpt [0] = 3，为什么难道不止于2点吗？
谢谢!!!
对于（i = 0;我< bigR.Length）我是，j;
; i ++）
{
if（（bigR [i] ==''+''）||（bigR [i] =='' - ''）||（bigR [i] = =''*''）||
（bigR [i] ==''/''））
{breakpt + = i;}
}
// breakpt [0] = 3 if type 100 + 200
MessageBox.Show（breakpt [0] .ToString（））;
for（j = 0; j< breakpt [0]; j ++）
{MessageBox.Show（j.ToString（））;
nums + = bigR [j];
}
Hi,
I''m trying to check and see if something other than numbers (either
the +, -, *, or /) are entered into a textbox, where bigR is what I
call the text in the textbox. I can get what was entered and where
along the string (the where part is the first section of below). I''m
running into trouble just after that. I tested what the value of
breakpt[0] and got 3, which it should be if entering something like
100 + 200. But when I run the for j = 0 to j = < breakpt[0], it
doesn''t stop at 2, but keeps going until the index is out of the
array.
If the messagebox says breakpt[0] = 3, why doesn''t j stop at 2?
Thanks!!!
Melanie
int i, j;
for(i = 0; i < bigR.Length; i++)
{
if ((bigR[i] == ''+'') || (bigR[i] == ''-'') || (bigR[i] == ''*'') ||
(bigR[i] == ''/''))
{breakpt += i;}
}
// breakpt[0] = 3 if type 100+200
MessageBox.Show(breakpt[0].ToString());
for (j = 0; j < breakpt[0]; j++)
{
MessageBox.Show(j.ToString());
nums += bigR[j];
}
breakpt的类型是什么？
首先使用breakpt + = i;; （没有[]，看起来像整数加法）
然后你使用breakpt [0];所以它不能是一个整数。
如果在j之前会发生什么？循环，你做
int max = breakpt [0];
然后结束循环j< MAX" ？
Hans Kesting
What is the type of "breakpt"?
First you use "breakpt += i;" (no [], looks like integer addition)
Then you use "breakpt[0];" so it can''t be an integer.
What happens if just before the "j" loop, you do
int max = breakpt[0];
and then end the loop on "j < max" ?
Hans Kesting
嗨再次，
breakpt是我在程序中先前定义的字符串（字符串） breakpt =
"";）。
当我说breakpt + = i时，我得到一串数字告诉我哪里有+，
- ，*或/已输入。 （如果我输入100 + 200/20，breakpt将是37）。
然后当我使用breakpt [0]时，它会给我字符串中的第一个字符。
我尝试了你建议的int max，但得到了和以前一样的东西 -
第二个消息框显示j从0开始直到崩溃时它是
数组。
我也试过说
for（j = 0; j< int.Parse（breakpt [0]）; j ++ ）
并得到一个错误（'int.Parse（字符串）的最佳重载方法匹配''
有一些无效的参数）。
帮助！任何想法???
谢谢！
Melanie
" Hans Kesting"写道：
Hi again,
breakpt is a string that I define earlier in the program (string breakpt =
"";).
When I say breakpt += i, I get a string of numbers that tell me where a +,
-, *, or / was entered. (if I entered 100+200/20 , breakpt would be "37").
Then when I use breakpt[0], it gives me the first character in the string.
I tried the int max thing you suggested, but get the same thing as before -
the second messagebox shows j going from 0 on up until it crashes when it''s
out of the array.
I also tried saying
for (j = 0; j < int.Parse(breakpt[0]); j++)
and got an error (The best overloaded method match for ''int.Parse(string)''
has some invalid arguments).
Help! Any ideas???
Thanks!
Melanie
"Hans Kesting" wrote:
melanieab写道：
melanieab wrote:
我正在检查并查看数字以外的其他内容（
+， - ，*或/）被输入到文本框中，其中bigR是我在文本框中调用文本的内容。我可以得到输入的内容和字符串中的
（其中部分是下面的第一部分）。我刚刚在那之后遇到了麻烦。我测试了
breakpt [0]的值是什么，得到3，如果输入类似
100 + 200的话应该是。但是当我运行for j = 0到j =< breakpt [0]，它不会停在2，但一直持续到索引超出
数组。
如果消息框说breakpt [0] = 3，为什么难道不止于2点吗？
谢谢!!!
对于（i = 0;我< bigR.Length）我是，j;
; i ++）
{
if（（bigR [i] ==''+''）||（bigR [i] =='' - ''）||（bigR [i] = =''*''）||
（bigR [i] ==''/''））
{breakpt + = i;}
}
// breakpt [0] = 3 if type 100 + 200
MessageBox.Show（breakpt [0] .ToString（））;
for（j = 0; j< breakpt [0]; j ++）
{MessageBox.Show（j.ToString（））;
nums + = bigR [j];
}
Hi,
I''m trying to check and see if something other than numbers (either
the +, -, *, or /) are entered into a textbox, where bigR is what I
call the text in the textbox. I can get what was entered and where
along the string (the where part is the first section of below). I''m
running into trouble just after that. I tested what the value of
breakpt[0] and got 3, which it should be if entering something like
100 + 200. But when I run the for j = 0 to j = < breakpt[0], it
doesn''t stop at 2, but keeps going until the index is out of the
array.
If the messagebox says breakpt[0] = 3, why doesn''t j stop at 2?
Thanks!!!
Melanie
int i, j;
for(i = 0; i < bigR.Length; i++)
{
if ((bigR[i] == ''+'') || (bigR[i] == ''-'') || (bigR[i] == ''*'') ||
(bigR[i] == ''/''))
{breakpt += i;}
}
// breakpt[0] = 3 if type 100+200
MessageBox.Show(breakpt[0].ToString());
for (j = 0; j < breakpt[0]; j++)
{
MessageBox.Show(j.ToString());
nums += bigR[j];
}
breakpt的类型是什么？
首先使用breakpt + = i; （没有[]，看起来像整数加法）
然后你使用breakpt [0];所以它不能是一个整数。
如果在j之前会发生什么？循环，你做
int max = breakpt [0];
然后结束循环j< MAX" ？
Hans Kesting
What is the type of "breakpt"?
First you use "breakpt += i;" (no [], looks like integer addition)
Then you use "breakpt[0];" so it can''t be an integer.
What happens if just before the "j" loop, you do
int max = breakpt[0];
and then end the loop on "j < max" ?
Hans Kesting
我也试过
int k =（int ）（breakpt [0]）
看起来应该可以工作（将字符转换为整数），但是不是。
" melanieab"写道：
I also tried
int k = (int)(breakpt[0])
which seems like it should work (converts characters to ints), but isn''t .
"melanieab" wrote:
嗨再次，
breakpt是我在程序前面定义的一个字符串（string breakpt =
"";）。
当我说breakpt + = i时，我得到一串数字，告诉我输入了+，
- ，*或/的位置。 （如果我输入100 + 200/20，breakpt将是37）。
然后当我使用breakpt [0]时，它会给我字符串中的第一个字符。
我尝试了int你建议的最大的东西，但得到与以前相同的东西 -
第二个消息框显示j从0开始直到它崩溃时，它是从阵列中出来的。
我也是尝试说
for（j = 0; j< int.Parse（breakpt [0]）; j ++）
并得到一个错误（最好的重载方法匹配''int.Parse（string） ''
有一些无效的论点。）
帮助！任何想法???
谢谢！
Melanie
Hans Kesting写道：
Hi again,
breakpt is a string that I define earlier in the program (string breakpt =
"";).
When I say breakpt += i, I get a string of numbers that tell me where a +,
-, *, or / was entered. (if I entered 100+200/20 , breakpt would be "37").
Then when I use breakpt[0], it gives me the first character in the string.
I tried the int max thing you suggested, but get the same thing as before -
the second messagebox shows j going from 0 on up until it crashes when it''s
out of the array.
I also tried saying
for (j = 0; j < int.Parse(breakpt[0]); j++)
and got an error (The best overloaded method match for ''int.Parse(string)''
has some invalid arguments).
Help! Any ideas???
Thanks!
Melanie
"Hans Kesting" wrote:
melanieab写道：
melanieab wrote:
我正在检查并查看数字以外的其他内容（
+， - ，*或/）被输入到文本框中，其中bigR是我在文本框中调用文本的内容。我可以得到输入的内容和字符串中的
（其中部分是下面的第一部分）。我刚刚在那之后遇到了麻烦。我测试了
breakpt [0]的值是什么，得到3，如果输入类似
100 + 200的话应该是。但是当我运行for j = 0到j =< breakpt [0]，它不会停在2，但一直持续到索引超出
数组。
如果消息框说breakpt [0] = 3，为什么难道不止于2点吗？
谢谢!!!
对于（i = 0;我< bigR.Length）我是，j;
; i ++）
{
if（（bigR [i] ==''+''）||（bigR [i] =='' - ''）||（bigR [i] = =''*''）||
（bigR [i] ==''/''））
{breakpt + = i;}
}
// breakpt [0] = 3 if type 100 + 200
MessageBox.Show（breakpt [0] .ToString（））;
for（j = 0; j< breakpt [0]; j ++）
{MessageBox.Show（j.ToString（））;
nums + = bigR [j];
}
Hi,
I''m trying to check and see if something other than numbers (either
the +, -, *, or /) are entered into a textbox, where bigR is what I
call the text in the textbox. I can get what was entered and where
along the string (the where part is the first section of below). I''m
running into trouble just after that. I tested what the value of
breakpt[0] and got 3, which it should be if entering something like
100 + 200. But when I run the for j = 0 to j = < breakpt[0], it
doesn''t stop at 2, but keeps going until the index is out of the
array.
If the messagebox says breakpt[0] = 3, why doesn''t j stop at 2?
Thanks!!!
Melanie
int i, j;
for(i = 0; i < bigR.Length; i++)
{
if ((bigR[i] == ''+'') || (bigR[i] == ''-'') || (bigR[i] == ''*'') ||
(bigR[i] == ''/''))
{breakpt += i;}
}
// breakpt[0] = 3 if type 100+200
MessageBox.Show(breakpt[0].ToString());
for (j = 0; j < breakpt[0]; j++)
{
MessageBox.Show(j.ToString());
nums += bigR[j];
}
breakpt的类型是什么？
首先使用breakpt + = i; （没有[]，看起来像整数加法）
然后你使用breakpt [0];所以它不能是一个整数。
如果在j之前会发生什么？循环，你做
int max = breakpt [0];
然后结束循环j< MAX" ？
Hans Kesting
What is the type of "breakpt"?
First you use "breakpt += i;" (no [], looks like integer addition)
Then you use "breakpt[0];" so it can''t be an integer.
What happens if just before the "j" loop, you do
int max = breakpt[0];
and then end the loop on "j < max" ?
Hans Kesting
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