程序没有做它应该 - Ç [英] Program not doing what it should - C
问题描述
我写的，从用户接收一系列数字节目（小于= 20），而最后一个'0'是指一系列的结束（不包括在系列存储）。 2阵列（X，Y）尺寸为20（0-19 + 1为'0'）必须为零，而m表示Y轴阵列器官的数量。
I wrote a program that receive from user a series of numbers (<=20) while the last '0' means end of series (not included in series storing). 2 arrays (x,y) size 20 (0-19 + 1 for the '0') must be zeros, and m means number of organs in Y array.
用户必须输入数字上升（这是确定4EX。1,2,2,3,7,8，...，0）和0课程结束，如果没有，相应的错误信息会出现，程序将自动关闭。
The user must enter numbers ascending (it is ok 4ex. 1,2,2,3,7,8,...,0) and end with a '0' of course, if not, appropriate error message will appear, and program will shut off.
我们可以肯定用户将保持在＆lt;输入= 20个号码
We can be sure the user will keep the <=20 numbers of input.
Ÿ阵列将是（如果一切正常使用X数组）的X，但没有重复排序后的数组。 M将Y轴的器官数量排除'0'当然。
Y array will be (if everything went ok with X array) a sorted array of X but without duplicates. 'm' will be number of organs in Y exclude '0' of course.
功能SIFT只能组织Y数组从主（）。
Function SIFT must only organize the Y array for being printed from main().
示例：
如果用户将在x存储：1,1,2,3,5,5,5,6
If user will store in X: 1,1,2,3,5,5,5,6
在屏幕将是：M = 5 Y = 1,2,3,5,6
On screen will be: m = 5 Y = 1,2,3,5,6
我的code：
#include <stdio.h>
#include <string.h>
void SIFT(int x_arr[ ], int y_arr[]);
int main ()
{
int x[20] = {0} , y[20] = {0};
int m=0,temp=0,curr=0,i=0,j=0;
printf("Please enter your numbers now:\n\n");
/*enter numbers one by one. if x[i+1] value < x[i] value, err msg.
when user want to end the series he must enter '0' which means end of string (it wont included in x[]) */
while ( ( temp = getchar() ) != '0' )
{
if (temp >= curr)
{
x[i] = temp;
curr = temp;
i++;
}
else
{
printf("The numbers are not at the right order !\n\nProgram will now terminate...\n\n");
}
}
SIFT(x,y);
for (i=0 ; y[i]=='0' ; i++) /*strlen(y) without ('0')'s includes*/
m++;
/*Prints m , y's organs*/
printf("\n\nm = %d",m);
printf("Y = ");
while (y[j]!='0')
{
printf ("%d ,",y[j]);
j++;
}
return 0;
}
void SIFT(int x_arr[ ], int y_arr[])
{
int i=0,j=0;
while (x_arr[i] != '0')
{
if (x_arr[i] == x_arr[i+1]) /*if current val. equals next val. -> jump dbl at x_arr*/
{
y_arr[j] = x_arr[i];
i+=2;
j++;
}
else
{
y_arr[j]=x_arr[i];
i++;
j++;
}
}
}
对于一些未知的原因，对于任何一种合法输入的我得到了这些数字是不是在正确的顺序......的错误消息...
For some unknown reason, for any kind of legal input I'm getting a "The numbers are not at the right order..." error message...
我会很乐意，如果有人可以修复它，所以它应该正常工作，因为到现在为止我所看到的一切是好像是OK ......
I will be more than happy if someone can fix it so it should work properly, because until now I can see everything is seems to be OK.....
感谢:( ...
推荐答案
的getchar（）不会做你认为它。阅读其描述（ http://pubs.opengroup.org/onlinepubs/9699919799/functions /getchar.html ）。
getchar() does not do what you think it does. Read its description ( http://pubs.opengroup.org/onlinepubs/9699919799/functions/getchar.html ).
您可以尝试 scanf（）的，而不是（的 http://pubs.opengroup.org/onlinepubs/9699919799/functions/scanf.html ），或更好，与fgets（）和的sscanf（）。
You can try scanf() instead ( http://pubs.opengroup.org/onlinepubs/9699919799/functions/scanf.html ), or better, fgets() and sscanf().
这篇关于程序没有做它应该 - Ç的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
