初始化时无法转换为`int' [英] Cannot convert to `int' in initialization
问题描述
以下程序有什么问题？
--- foo.cpp ---
struct Foo {};
int main（）
{
Foo foo1，foo2;
for（int i = 0，foo1 = foo2 ;;）; //第5行
返回0;
}
---------------
---汇编---
// GNU gcc / gpp 3.4.1
$ gpp foo.cpp
foo.cpp：在函数`int main（）''中：
foo.cpp：5：错误：无法将`Foo'转换为初始化中的'int''
-------------------
Alex Vinokur
电子邮件：alex DOT vinokur AT gmail DOT com
http://mathforum.org/library/view/10978.html
http://sourceforge.net/users/alexvn
What is wrong in program below?
--- foo.cpp ---
struct Foo {};
int main ()
{
Foo foo1, foo2;
for (int i = 0, foo1 = foo2; ; ); // Line#5
return 0;
}
---------------
--- Compilation ---
// GNU gcc/gpp 3.4.1
$ gpp foo.cpp
foo.cpp: In function `int main()'':
foo.cpp:5: error: cannot convert `Foo'' to `int'' in initialization
-------------------
Alex Vinokur
email: alex DOT vinokur AT gmail DOT com
http://mathforum.org/library/view/10978.html
http://sourceforge.net/users/alexvn
推荐答案
gpp foo.cpp
foo.cpp：在函数`int main（）''中：
foo.cpp：5：错误：初始化时无法将`Foo''转换为'int''
-------------------
Alex Vinokur
电子邮件：啤酒x DOT vinokur AT gmail DOT com
http://mathforum.org /library/view/10978.html
http：// sourceforge。 net / users / alexvn
gpp foo.cpp
foo.cpp: In function `int main()'':
foo.cpp:5: error: cannot convert `Foo'' to `int'' in initialization
-------------------
Alex Vinokur
email: alex DOT vinokur AT gmail DOT com
http://mathforum.org/library/view/10978.html
http://sourceforge.net/users/alexvn
* Alex Vinokur：
* Alex Vinokur:
以下程序有什么问题？
--- foo.cpp ---
struct Foo {};
int main（）
{
Foo foo1，foo2;
for（int i = 0，foo1 = foo2; ; ）; //第5行
返回0;
}
What is wrong in program below?
--- foo.cpp ---
struct Foo {};
int main ()
{
Foo foo1, foo2;
for (int i = 0, foo1 = foo2; ; ); // Line#5
return 0;
}
很多错，但它没有_compile_的原因是赋值
''foo1 = foo2''产生一个需要条件的Foo值 -
条件必须是一个可以隐式转换为bool的值。
-
答：因为它弄乱了人们通常阅读文字的顺序。
问：为什么这么糟糕东西？
A：热门发布。
问：usenet和电子邮件中最烦人的是什么？
Much wrong, but the reason it doesn''t _compile_ is that the assignment
''foo1 = foo2'' produces a Foo value where a condition is required -- a
condition must be a value that can be implicitly converted to bool.
--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
" Alex Vinokur" <人**** @ big-foot.com>在消息中写道
news：30 ************* @ uni-berlin.de ...
"Alex Vinokur" <al****@big-foot.com> wrote in message
news:30*************@uni-berlin.de...
以下程序有什么问题？
--- foo.cpp ---
struct Foo {};
int main（）
{
Foo foo1，foo2;
for（int i = 0，foo1 = foo2 ;;）; //第5行
声明
int i = 0，foo1 = foo2
声明两个int类型的变量：i和foo1。第一个用值$ 0初始化为
。第二个应该用值foo2初始化，但是
没有从这个值转换为int。
返回0;
}
What is wrong in program below?
--- foo.cpp ---
struct Foo {};
int main ()
{
Foo foo1, foo2;
for (int i = 0, foo1 = foo2; ; ); // Line#5
The declaration
int i = 0, foo1 = foo2
declares two variables of type int: i and foo1. The first is initialized with
the value 0. The second is supposed to be initialized with the value foo2, but
there is not conversion from this value to an int.
return 0;
}
为了好玩，试试：
#include < iostream>
#include< typeinfo>
struct Foo {
operator int（）const {return 5; }
};
int main（）
{
Foo foo1，foo2;
for（int i = 0，foo1 = foo2 ;;）{
std :: cout<< typeof foo1 = << typeid（foo1）.name（）<< " \ n";
std :: cout<< foo1 = << foo1<< " \ n";
休息;
};
返回0;
}
Jonathan
For fun, try:
#include <iostream>
#include <typeinfo>
struct Foo {
operator int() const { return 5; }
};
int main ()
{
Foo foo1, foo2;
for (int i = 0, foo1 = foo2; ; ) {
std::cout << "typeof foo1 = " << typeid(foo1).name() << "\n";
std::cout << "foo1 = " << foo1 << "\n";
break;
};
return 0;
}
Jonathan
这篇关于初始化时无法转换为`int'的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
