无法弄清楚这一点 [英] Can't figure this out

问题描述

各位大家好，


我只是有一点问题，我不知道它是什么：


[gongds @ labtherm] [15:52:28] $ cat test.c

#include< stdio.h>

int main（void）

{

char * s =" CAT";


*（s + 1）='''B'';

printf（"％s"，s）;


返回（0）;

}

[gongds @ labtherm] [15:52:32] $ gcc -o test test.c

[gongds @ labtherm] [15:52:40] $ ./test

分段错误（核心倾销）

[gongds @ labtherm] [15:52:42] $


我在这里做错了什么？只是为了获取信息，这个代码是在Windows 98机器上使用GCC在cygwin下编译的。


感谢您的帮助，

干杯！


---

Joseph

解决方案

cat test.c

#include< stdio.h>

int main（无效）

{

char * s =" CAT";


*（s + 1）=''B'';

printf（" ％s"，s）;


返回（0）;

}

[gongds @ labtherm] [15:52 ：32]

gcc -o test test.c

[gongds @ labtherm] [15:52:40]

< blockquote> ./ test

分段错误（核心转储）

[gongds @ labtherm] [15:52:42]

Hello everybody,

I just have a little problem, and I just can''t figure out what it is:

[gongds @ labtherm][15:52:28]$ cat test.c
#include <stdio.h>
int main (void)
{
char* s = "CAT";

*(s+1) = ''B'';
printf("%s", s);

return (0);
}
[gongds @ labtherm][15:52:32]$ gcc -o test test.c
[gongds @ labtherm][15:52:40]$ ./test
Segmentation fault (core dumped)
[gongds @ labtherm][15:52:42]$

Just what am I doing wrong here? Just for information this ''code'' was
compiled using GCC under cygwin, on a windows 98 machine.

Thank-you for any help,
Cheers!

---
Joseph

解决方案

cat test.c
#include <stdio.h>
int main (void)
{
char* s = "CAT";

*(s+1) = ''B'';
printf("%s", s);

return (0);
}
[gongds @ labtherm][15:52:32]

gcc -o test test.c
[gongds @ labtherm][15:52:40]

./test
Segmentation fault (core dumped)
[gongds @ labtherm][15:52:42]

这篇关于无法弄清楚这一点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！