使用字典创建地址簿 [英] Creating an adress-book using dictionary
问题描述
i我目前正在创建一个'地址簿'python，我想用词典吗？
计划：
我正在尝试创建一个有索引的小地址簿
指数 - 认为是合适的 - 可能是地址簿中的'昵称'我想给出一些选择：
用户的昵称可以节省一些：
a。保存一个人的姓名，一个人的地址以及随后的那个人的电话号码。
好 - 到目前为止很好： - 我想使用词典， 我想要这样的清单。例如
myList = [[Bill，Butcher，4433345411]，[Billiboy，2 Rue Rivoli，0994399394800838383]]
然后，如果我想看到某个联系人，我会使用更多代码来搜索模式。
然后我需要弄清楚如何用字典做什么？
好 - 我可以做一些起点 - 使用字典：
i可能从这开始：
my_dict = {Don ：{name：Donald Jones，address：1 Rue Rivoli Paris，phone：9444444411}，< br />
&NBSP; &NBSP; &NBSP; &NBSP; Joseph：{name：Joseph Boy，address：3 Tivoli Paris，phone：0800838383}< br />
&NBSP; &NBSP; &NBSP; &NBSP; &NBSP; Bilbo：{name：Bilbo Baggin，地址：4 White House Washington，phone：08055550838383}< br />
&NBSP; &NBSP; &NBSP; < br />
&NBSP; &NBSP; &NBSP; &NBSP;} &NBSP; &NBSP; &NBSP; &NBSP;
但是如何访问我创建的记录：我可以使用
$访问记录b $ b
my_dict [Don] [name]
或类似如此
my_dict [Bilbo] [电话]
顺便说一句：Python字典中的键往往是唯一的。在我的地址簿中有一个联系人列表，重要的是 - 应该没有两次名称。 那是圣徒 - 我们看到了这样的解决方案：
[python]
contacts = {}
contacts [' Don'] = [1 Rue Rivoli，9444444411]
联系人['Joseph'] = [3 Tivoli，0800838383]
所以将数据添加到词典是基于访问运算符[]。
问题是：如何扩展scipt有点
我应该使用
- 原始输入
- arg.pop
你会如何扩展剧本！？
你怎么说！？
很高兴收到你的来信
我尝试过：
但是如何访问我创建的记录：我可以使用
my_dict [Don] [name]
或类似因此
my_dict [Bilbo ] [电话]
顺便说一下：Python词典中的键t结束是独一无二的。在我的地址簿中有一个联系人列表，重要的是 - 应该没有两次名称。 那是圣徒 - 我们看到我可以得到这样的解决方案：
[python]
contacts = {}
contacts ['Don'] = [1 Rue Rivoli，9444444411 ]
联系人['Joseph'] = [3 Tivoli，0800838383]
所以将数据添加到字典是基于访问运算符[]。
问题是：如何使用
- 原始输入
- arg.pop p $ p>解决方案
看看序列化和Python对象的反序列化：https://code.tutsplus.com/tutorials/serialization-and-deserialization-of-python- objects-part-1 - cms-26183 [ ^ ]
hello dear experts
i am currently creating an 'adress book' python where i want to use dictionaries?
the plan:
I'm trying to create an little adress-book that has got an index
the index - think would be apropiate - could be the 'nickname' in the adress-book I want to give some options:
with the nickname the user can do some savings:
a. save a name of a person, the address of a person and subsequently the phone-number of that person.
well - so far so good: - i want to use use a dictionaries, i want to have such a list. e.g
myList = [["Bill","Butcher", "4433345411"],["Billiboy","2 Rue Rivoli ", "0994399394800838383"]]
And then if I wanted to see a certain contact I would just use some more code to search for a pattern.
And then i need to figure out how to do it with a dictionary?
well - i could do some starting points - with the usage of a dictionary:
i could probably start with this:
my_dict = {"Don": {"name": "Donald Jones", "address": "1 Rue Rivoli Paris ", "phone": "9444444411"}, <br /> "Joseph": {"name": "Joseph Boy", "address": "3 Tivoli Paris", "phone": "0800838383"}<br /> "Bilbo": {"name": "Bilbo Baggin", "address": "4 White House Washington", "phone": "08055550838383"}<br /> <br /> }
But how to get access to the records that i have created: well i can access records using
my_dict["Don"]["name"]
or like so
my_dict["Bilbo"]["phone"]
by the way: Keys in a Python dictionary tend to be unique. Having a list of contacts in my adressbook the important thing is - there should be no name twice. That saind - we see that i can have the solution like this:
[python]
contacts = {}
contacts['Don'] = ["1 Rue Rivoli", 9444444411]
contacts['Joseph'] = ["3 Tivoli", 0800838383]
so adding data to a dictionary is based on the access operator [].
the question is: how to extend the scipt a bit
should i make use of
- raw input
- arg.pop
how would you extend the script!?
what do you say!?
love to hear from you
What I have tried:
But how to get access to the records that i have created: well i can access records using my_dict["Don"]["name"] or like so my_dict["Bilbo"]["phone"] by the way: Keys in a Python dictionary tend to be unique. Having a list of contacts in my adressbook the important thing is - there should be no name twice. That saind - we see that i can have the solution like this: [python] contacts = {} contacts['Don'] = ["1 Rue Rivoli", 9444444411] contacts['Joseph'] = ["3 Tivoli", 0800838383] so adding data to a dictionary is based on the access operator []. the question is: how to extend the scipt a bit should i make use of - raw input - arg.pop解决方案Take a look at Serialization and Deserialization of Python Objects: https://code.tutsplus.com/tutorials/serialization-and-deserialization-of-python-objects-part-1--cms-26183[^]
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