如何创建从活动目录读取所有节点/子节点的树视图。 [英] How do I create a treeview that reads all nodes/childnodes from active directory.
问题描述
我正在尝试用树视图重新创建我的AD结构。
我使用了用户Smirnov的示例代码： Active Directory树视图仿真ASP.NET论坛 [ ^ ]
一个非常好的例子，谢谢！
这是我的问题：
这段代码适用于树视图的前两个级别，但后来对于像我这样的初学者来说变得很复杂。我试图在OU名称中添加节点位置以进行调试。有人可以告诉我如何做到这一点。 :)
我想我正试图用错误的方法解决这个问题。必须有一个通用的解决方案来添加Active Directory中的所有节点和所有子节点。稍后我也会尝试添加电脑。
AD - 结构| Flickr [ ^ ]
应用程序输出 [ ^ ]
Hi,
I'm trying to re-create my AD-structure with treeview.
I have used the example code from the user Smirnov: Active Directory Tree View Emulation | The ASP.NET Forums[^]
A very good example, thank you!
This is my problem:
This code works for the first two levels of treeview but later it becomes complicated for a beginner like me. I have tried to add node position in the OU-name for debugging purposes. Could someone please show me how to do this. :)
I guess I'm trying to solve this problem with the wrong method. There must be a general solution for adding all nodes and all childnodes from Active Directory. Later I will try to add computers also.
AD-structure| Flickr[^]
Application output[^]
using System;
using System.Collections.Generic;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.DirectoryServices;
namespace tree2
{
public partial class Form1 : Form
{
int n = 0;
int n2 = 0;
int n3 = 0;
string server;
string level1;
public Form1()
{
InitializeComponent();
server = "LDAP://servername";
level1 = "OU=MyCompany,OU=Companys,dc=my_dc,dc=local";
GetAllNodes();
}
private void GetAllNodes()
{
GetNodes(level1, 0);
}
// Modified code from Smirnov at https://forums.asp.net/post/4381459.aspx
private void GetNodes(string path, int level)
{
using (DirectoryEntry entryToQuery = new DirectoryEntry(server + path))
{
DirectorySearcher ouSearch = new DirectorySearcher(entryToQuery);
ouSearch.Filter = "(objectClass=organizationalUnit)";
ouSearch.SearchScope = SearchScope.OneLevel;
ouSearch.PropertiesToLoad.Add("name");
SearchResultCollection allOUS = ouSearch.FindAll();
foreach (SearchResult oneResult in allOUS)
{
string ou = oneResult.Properties["name"][0].ToString();
string prefix = string.Empty;
for (int i = 0; i < level; i++)
{
prefix += "*";
}
outbox.AppendText(prefix + ou + Environment.NewLine);
int stars = countstars(prefix);
if (stars == 0) treeView1.Nodes.Add(ou);
if (stars == 1)
{
treeView1.Nodes[0].Nodes.Add(ou + " 0");
n++;
}
if (stars == 2)
{
treeView1.Nodes[0].Nodes[n-1].Nodes.Add(ou+" 0." + (n - 1).ToString());
n2++;
}
if (stars == 3)
{
// Not working...
// treeView1.Nodes[0].Nodes[n2].Nodes[0].Nodes.Add(ou + " 0." + (n2).ToString() + ".0");
n3++;
}
GetNodes("OU=" + ou + "," + path, level + 1);
}
}
}
int countstars(string a)
{
int stars = 0;
for (int i = 0; i < a.Length; i++)
{
if (a[i] == '*') stars++;
}
return stars;
}
}
}
我尝试过：
What I have tried:
I have tried different approaches.
* Working with previous, this and next OU and decide where to put it in Treeview.
* I have tried debugging and add some local variables but it gets very messy.
* I have tried with parent node
推荐答案
注意：我没有可以试验的网络。附件是一些通用代码，用于映射文本文件，其中行结构反映树结构，并重复一些文本分隔符以指示节点级别：注意，这是我前一段时间写的代码，并且不包括强大的错误检查; 使用时需要您自担风险。
建议您查看：[ ^ ]
这里的代码是，imho，更简单，而且，我认为可以很容易地适应你：[ ^ ]
并且，CodeProject是你的朋友：从这里开始：[ ^ ]
另见：[ ^ ]，[ ^ ]，[ ^ ]
代码示例：
Note: I do not have a network to experiment with. Attached is some generic code to map a text file where the line structure reflects a tree structure with some text-delimiter repeated to indicate node level: note, this is code I wrote some time ago, and does not include robust error-checking; use as is at your own risk.
Suggest you review: [^]
The code here is, imho, simpler, and, I think can be easily adapted by you: [^]
And, CodeProject is your friend: start here: [^]
also see: [^], [^], [^]
Code example:
using System;
using System.Collections.Generic;
using System.Windows.Forms;
namespace YourNameSpace
{
public static class StringToTreeView
{
private static char[] linesplitter;
private static TreeNode node;
public static Dictionary<int, TreeNode> levelToNode = new Dictionary<int, TreeNode>();
public static void Map(string source, char linesplit, char levelindicator, ref TreeView tv)
{
levelToNode.Clear();
string[] lines = source.Split(new char[] { linesplit }, StringSplitOptions.RemoveEmptyEntries);
TreeNode parentNode;
for (int i = 0; i < lines.Length; i++)
{
string line = lines[i];
string trimmed = line.TrimStart(levelindicator);
// fast as Linq !
// https://stackoverflow.com/a/541994/133321
int level = line.Length - trimmed.Length;
node = new TreeNode(trimmed);
levelToNode[level] = node;
if (level == 0)
{
tv.Nodes.Add(node);
}
else
{
if (levelToNode.TryGetValue(level - 1, out parentNode))
{
parentNode.Nodes.Add(node);
}
else
{
throw new AccessViolationException(
\\\\ error）：level超过当前使用{ node.Text} \r\\\
）;
}
}
}
}
}
}
"\r\nerror in node definition: level exceeds current use {node.Text}\r\n"); } } } } } }
一个用法示例：
string src = @"one,*two,**three,four,*five,**six,***seven,****eight,**nine";
StringToTreeView.Map(src, ',', '*', ref YOURTREEVIEW);
这篇关于如何创建从活动目录读取所有节点/子节点的树视图。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
