读取每个特定节点的所有XML子节点 [英] Read all XML child nodes of each specific node

问题描述

我需要读取我的<Imovel>标记的所有Child Nodes，问题是我的XML文件中有多个(一个)<Imovel>标记，并且每个<Imovel>标记之间的区别是一个名为ID的属性.

I need to read all the Child Nodes of my <Imovel> tag, the problem is that I has more than 1 (one) <Imovel> tag in my XML file, and the difference between each <Imovel> tag is an attribute called ID.

这是一个示例

<Imoveis>
   <Imovel id="555">
      <DateImovel>2012-01-01 00:00:00.000</DateImovel>
      <Pictures>
          <Picture>
              <Path>hhhhh</Path>
          </Picture>
      </Pictures>
      // Here comes a lot of another tags
   </Imovel>
   <Imovel id="777">
      <DateImovel>2012-01-01 00:00:00.000</DateImovel>
      <Pictures>
          <Picture>
              <Path>tttt</Path>
          </Picture>
      </Pictures>
      // Here comes a lot of another tags
   </Imovel>
</Imoveis>

我需要读取每个<Imovel>标记的所有标记，并且在我在<Imovel>标记中进行的每个验证的最后，我需要执行另一个验证.

I need read all tags of each <Imovel> tag, and in the end of each validation that I do in my <Imovel> tag I need to do another validation.

所以，我想我需要做2个(两个)foreach或for和foreach，我对LINQ不太了解，但是请遵循我的示例

So, I think I need to do 2 (two) foreach or a for and a foreach, I don't understand very well about LINQ but follow my sample

XmlReader rdr = XmlReader.Create(file);
XDocument doc2 = XDocument.Load(rdr);
ValidaCampos valida = new ValidaCampos();

//// Here I Count the number of `<Imovel>` tags exist in my XML File                        
for (int i = 1; i <= doc2.Root.Descendants().Where(x => x.Name == "Imovel").Count(); i++)
{
    //// Get the ID attribute that exist in my `<Imovel>` tag
    id = doc2.Root.Descendants().ElementAt(0).Attribute("id").Value;

    foreach (var element in doc2.Root.Descendants().Where(x => x.Parent.Attribute("id").Value == id))
    {
       String name = element.Name.LocalName;
       String value = element.Value;
    }
}

但是在我的foreach语句中效果不佳，因为我的<Picture>标记及其父标记没有ID属性.

But doesn't work very well, in my foreach statement because my <Picture> tag, her parent tag don't has an ID attribute.

有人可以帮我做这种方法吗?

Somebody can help me to do this method ?

推荐答案

您应该可以使用两个foreach语句来做到这一点:

You should be able to do this with two foreach statements:

foreach(var imovel in doc2.Root.Descendants("Imovel"))
{
  //Do something with the Imovel node
  foreach(var children in imovel.Descendants())
  {
     //Do something with the child nodes of Imovel.
  }
}

这篇关于读取每个特定节点的所有XML子节点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！