我用C ++实现了迭代解决方案 [英] To I achieve iteration solution in C++

问题描述

我正在编写以下函数（detectHappy）中的代码，该代码将检查数字是否为幸福数字，仅适用于10个周期（迭代）。我的功能应该是：



- 查找数字的位数总和。



- 检查在第1点获得的结果。如果为1，则将值1赋值给变量'finalNumber'，否则再次执行第1点，直到获得的数字为1或直到循环次数增加到10.



- 将迭代值赋给变量'cycle_no'。



我不应输入，输出或声明任何其他函数。我只需编写已经在那里声明的函数的主体，它将使它在我的课程中提供的shell上运行...



我尝试过的程序写编译但没有给出正确的结果（例如，数字6在10个周期后产生值32765而不是预期的145.我现在缺乏想法，我将不胜感激任何帮助。谢谢你提前。



我尝试了什么：

I am writing a code in the following function(detectHappy) that will check whether a number is a happy number or not, for 10 cycles (iterations) only. My function should :

-Find the sum of the digits of the number.

-Check the result obtained in point 1. If it is 1, assign value 1 to the variable 'finalNumber', else again execute point 1, till the number obtained is 1 or till the number of cycle increases to 10.

-Assign the iteration value to the variable 'cycle_no'.

I am not supposed to input, output or declare any additional functions. I just have to write the body of the function already declared there that will make it work on the shell offered in my course...

The programme I have attempted to write compiles but does not give the correct results (e.g number 6 generates the value 32765 after 10 cycles instead of the expected 145. I am now short of ideas and I will be grateful for any assistance. Thank you in advance.

What I have tried:

/*Question      : Write your code to find whether the number is a happy number or not (for max 10 cycles).
int number      : The number to be determined whether it is happy or not
int finalNumber : Store the resultant value in this variable
int cycle_no    : Store the number of iterations done to determine whether the 'number' is happy or not */

void detectHappy(int number, int &finalNumber, int &cycle_no) {

    //Write your solution code below this line
    int sum = 0;
    int i = 1;
    do{
        sum += (number%10)*(number % 10);
        number /=10;
        if (sum == 1){
            finalNumber = 1;
            break;
        }
        else {
            number = sum;
            ++number;
        }
        cycle_no = ++i;
    }
    while (i < 10);
}

推荐答案

你错过了数字位数的内循环。尝试

You missed the inner loop on number's digits. Try

void detectHappy(int number, int &finalNumber, int &cycle_no)
{
  for (cycle_no=1; cycle_no <= 10; ++cycle_no)
  {
    finalNumber = 0;
    while (number)
    {
      finalNumber += (number % 10)  * (number % 10);
      number /= 10;
    }
    if (finalNumber == 1)
      return;
    number = finalNumber;
  }
}

当你不明白你的代码在做什么时，答案是 debugger 。

快乐号码 - 维基百科 [ ^ ]

从此链接获取示例并与您的代码进行比较。



有一个工具可以让你看到你的代码在做什么，它的名字是调试器。它也是一个很好的学习工具，因为它向你展示了现实，你可以看到哪种期望与现实相符。

当你不明白你的代码在做什么或为什么它做它做的时候，答案就是答案是调试器。

使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量。



调试器 - 维基百科，免费的百科全书 [ ^ ]



掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]

使用Visual Studio 2010进行基本调试 - YouTube [ ^ ]

调试器在这里向您展示您的代码正在做什么，您的任务是与什么进行比较应该这样做。

调试器中没有魔法，它没有找到错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

When you don't understand what your code is doing, the answer is debugger.
Happy number - Wikipedia[^]
Get an example from this link and compare with what your code is doing.

There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

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