Php更新数据库无法正常工作 [英] Php update database is not working

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本文介绍了Php更新数据库无法正常工作的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个应该更新数据库详细信息的代码,但它不起作用。



有一条错误消息说



i have a code which should update the database details, However it doesn't work.

There is a Error message which says

Quote:

错误你的SQL语法有错误;查看与您的MySQL服务器版本对应的手册,以便在'='Nic'附近使用正确的语法,fullname ='F_Name',address ='Address',contact ='Contact',color ='Col'在第1行

ErrorYou have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= 'Nic',fullname = 'F_Name',address = 'Address',contact = 'Contact',color = 'Col' at line 1





我的尝试:





What I have tried:

$connnect= mysqli_connect ("localhost","root","1234","latgsjason");
    if (mysqli_connect_error()){
    echo"Failed to Connect";
    }
        $VRegno= $_POST['V_Regno'];
        $Nic=$_POST['Nic'];
        $FullName=$_POST['F_Name'];
        $Address=$_POST['Address'];
        $Contact=$_POST['Contact'];
        $Color=$_POST['Color'];
				
        $sql = "Update customer SET nic='$Nic',fullname ='$FullName',address='$Address',contact='$Contact',color='$Color' where veh_regno='$VRegno'";
        if(!mysqli_query($connnect,$sql))
        {
            die("Error".mysqli_error($connnect));
        }
        echo"Update Successfully ";
        if(!isset($conn)){
        mysqli_close($conn);
        }

推荐答案

connnect = mysqli_connect(localhost,root,1234,latgsjason);
if(mysqli_connect_error()){
echo连接失败;
}
connnect= mysqli_connect ("localhost","root","1234","latgsjason"); if (mysqli_connect_error()){ echo"Failed to Connect"; }


VRegno =


_POST ['V_Regno'];
_POST['V_Regno'];


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