你究竟如何使用json_decode将javascript数组传递给php？ [英] How exactly do you use json_decode to pass a javascript array to php?

问题描述

这就是我将我的php数组转换为javascript的方式

This is how I got my php array to javascript

echo 'var daysofweek = '.json_encode($daysofweek).';';

现在我知道json_decode可以做相反的事情，但问题是我不知道这样做的语法。

Now I am aware that json_decode can do the opposite, however the problem is I don't know the syntax to do so.

我试过：

<script>
var array_days = new Array();

array_days[] = "psdfo";
array_days[] = "bsdf";

<?php
$array_days = json_decode(?>array_days<?php);?>

</script>

是的，我很无能为力。

我忘记了提到我想通过post发送一个数组，包含有关javascript动态创建的所有表单值的所有信息。否则，我不知道要查找哪个名称=，因为它将由用户决定。除非其他人有替代解决方案...

I forgot to mention that I want to send an array through post, having all my information regarding all the form values dynamically created by javascript. Otherwise, I wouldn't know which name="" to look for as it will be decided by the user. Unless someone else has an alternative solution...

推荐答案

<script>
var array_days = new Array();

array_days[] = "psdfo";
array_days[] = "bsdf";

<?php
$array_days = json_decode(?>array_days<?php);?>

</script>

我对此部分一无所知......这是javascript ？如果是这样，你需要使用JSON解析器，如JSON2.js https://github.com/douglascrockford/ JSON-js

I'm clueless in this part... is this javascript? if so, you need to use a JSON Parser like the JSON2.js https://github.com/douglascrockford/JSON-js

此文件创建一个Javascript JSON对象，允许您将JSON字符串解析为Javascript对象。 （你总是可以使用eval（）但它不会阻止可能的恶意代码......）或者反过来......从Javascript对象转换为JSON字符串。

this file creates a Javascript JSON Object which allows you to parse a JSON string to a Javascript object. (you can always use eval() but it won't prevent against possible malicious code...) or the other way around... from a Javascript Object transform into a JSON string.

转换为JSON字符串后，您只需要通过AJAX将数据发送到PHP文件，例如：

After converting to a JSON string you just need to send the data through AJAX to a PHP file, like:

var data = {
   key: value,
   key2: value2 
},
JSON = JSON.stringify(data);

$.ajax({
    url: 'php_file.php',
    type: 'POST',
    data: JSON,
    success: function(data){
        alert(data)
    }
});

（我使用jQuery保存一些行...）

(I'm using jQuery to save some lines...)

然后在php_file.php上你会有这样的东西：

Then on the php_file.php you would have something like this:

<?php 
    $json = json_decode($_POST['data']);

    foreach($json as $value){
       //Do something with it!
    }
?>

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