嵌套复杂JSON中的搜索键 [英] Search key in nested complex JSON

问题描述

我必须通过JavaScript或jQuery搜索嵌套JSON中的密钥。在我的JSON对象中，所有键都是唯一的。我自己尝试了一些解决方案，但它们没有用。
这是我的代码：

I have to search for a key in nested JSON by JavaScript or by jQuery. In my JSON object all the keys are unique. I tried some solutions myself but they did not work. Here is my code:

json = {
    "app": [{
        "Garden": {
            "Flowers": {
                "Red flower": "Rose",
                "White Flower": "Jasmine",
                "Yellow Flower": "Marigold"
            }
        },
        "Fruits": {
            "Yellow fruit 1": "Mango",
            "Green fruit 2": "Guava",
            "White Flower 3": "groovy"
        },
        "Trees": {
            "label": {
                "Yellow fruit 2": [{"type a":"Pumpkin", "type b": "Banana",..}],
                "White Flower 2": ["Bogan 1", "Bogan 2", ...] 
            }
        }],...
    }

如何搜索对于给定对象中的特定键？

How can I search for a specific key in given object?

如果我传递 lookup（json，type a）它应该返回Pumpkin，或者如果我搜索白花2它应该返回 [Bogan 1，Bogan 2，...]

If I pass lookup(json, "type a") it should return "Pumpkin", OR If I search for "White Flower 2" it should return ["Bogan 1", "Bogan 2", ...]

这是我的尝试，这是行不通的：

Here is my try, which is not working:

function lookup(obj, k){
    for (key in obj){
        value = obj[key];
        if (k == key) return [k, value];
        if (type(value) == "Object"){
            var y = lookup(value, k);
            if (y && y[0]== k)return y;
        }
        if(type(value) == "Array"){
            for (i in value)
            {
                var x = lookup(value[i], k);
                if (x && x[0]== k)return x; 
            }
        }
        console.log(key, value);
        return null;
    } 
}

要查找对象的类型，我是使用此代码：

To find the type of the object, I'm using this code:

function type(object){
    var stringConstructor = "test".constructor;
    var arrayConstructor = [].constructor;
    var objectConstructor = {}.constructor;

    if (object === null) {
        return "null";
    }
    else if (object === undefined) {
        return "undefined";
    }
    else if (object.constructor === stringConstructor) {
        return "String";
    }
    else if (object.constructor === arrayConstructor) {
        return "Array";
    }
    else if (object.constructor === objectConstructor) {
        return "Object";
    }
    else {
        return "null";
    }
}

推荐答案

你'比你想象的更近 - 移动返回null; 用于中的（键入obj）是主要的东西;否则，只要对象中的第一个键不匹配，您就会放弃。只有在搜索完所有键后才放弃。

You're closer than you think - moving return null; out of for (key in obj) is the main thing; otherwise, you're giving up as soon as the first key in the object doesn't match. Only give up after searching all the keys.

function lookup(obj, k) {
  for (key in obj) {

    value = obj[key];
    if (k == key) return [k, value];

    if (type(value) == "Object") {
      var y = lookup(value, k);
      if (y && y[0] == k) return y;
    }
    if (type(value) == "Array") {
      // for..in doesn't work the way you want on arrays in some browsers
      //
      for (var i = 0; i < value.length; ++i) {
        var x = lookup(value[i], k);
        if (x && x[0] == k) return x;
      }
    }
  }

  return null;
}

var json = {
  "app": [{
    "Garden": {
      "Flowers": {
        "Red flower": "Rose",
        "White Flower": "Jasmine",
        "Yellow Flower": "Marigold"
      }
    },
    "Fruits": {
      "Yellow fruit 1": "Mango",
      "Green fruit 2": "Guava",
      "White Flower 3": "groovy"
    },
    "Trees": {
      "label": {
        "Yellow fruit 2": [{
          "type a": "Pumpkin",
          "type b": "Banana"
        }],
        "White Flower 2": ["Bogan 1", "Bogan 2"]
      }
    }
  }]
}

function type(object) {
  var stringConstructor = "test".constructor;
  var arrayConstructor = [].constructor;
  var objectConstructor = {}.constructor;

  if (object === null) {
    return "null";
  } else if (object === undefined) {
    return "undefined";
  } else if (object.constructor === stringConstructor) {
    return "String";
  } else if (object.constructor === arrayConstructor) {
    return "Array";
  } else if (object.constructor === objectConstructor) {
    return "Object";
  } else {
    return "null";
  }
}

console.log(lookup(json, 'type a'));
console.log( lookup(json, 'White Flower 2') );

ps没有JSON对象这样的东西。如果它不是字符串，那么它不是JSON。您正在搜索JavaScript对象。

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