我怎么能同时询问一个数字是偶数/奇数还是正数/负数？ [英] How can I ask if a number is even/odd and positive/negative at the same time?

问题描述

如何同时询问一个数字是偶数/奇数还是正数/负数？

我已经完成了程序，询问数字是正数还是负数，但是我不知道如何添加（输入％2 == 0）。



谢谢。



我尝试过：

  int  main（）
 {
  int 输入; 
  cout < <  Please  输入  a  number \ n; 
  cout << ： 
  cin >>输入; 
 
 
 如果 （输入 >  0）{
 
  cout < <  输入<<     a   positive  number<< ENDL; 
 
 }  
  else   if  （输入 == 0）
 {
 
  cout < <   input <<       positive     negative   number  << ENDL; 
 }  
  else  
 {
  cout < <   input <<     a   negative   number  << ENDL; 
 }  
  return  0; 
 }  

解决方案

这是算法的一个很好的例子首先，编码第二。

这里的策略是分而治之 - 首先找出输入单独的正面性和均匀性，然后根据这些结果的组合做出决定。

使用此伪代码作为指南：

 GET输入
 SET isEven = 0 //默认为奇数
 SET isPositive = 0 //默认为中性
 
 //确定正数
 IF（输入> 0）THEN 
 SET isPositive = 1 //为正
 ELSE IF（输入< 0）THEN 
 SET isPositive = -1 //为负
 
 //确定均匀度
 IF（输入％2 == 0）THEN 
 SET isEven = 1 //甚至是
 
 //基于积极性和均匀度的综合发现的决定
 IF（isPositive == 1 AND isEven == 1）THEN 
 PRINT'输入是正的和偶数。'
 //自己弄清楚其余的... 
 ELSE IF（）THEN 
 // ... 
 ELSE 
 // ... 

How can I ask if a number is even/odd and positive/negative at the same time?
I've already done the program that asks if a number is positive or negative, but I have no idea how to add (input % 2 == 0) into it.

Thank you.

What I have tried:

int main()
{
        int input;
        cout << "Please enter a number\n";
        cout << ":";
        cin >> input;
    
    
        if (input > 0)         {
            
            cout << input << " is a positive number" << endl;
            
        }
        else if (input == 0)
        {
            
            cout << input << " is neither positive nor negative number " << endl;
        }
        else
        {
            cout << input << " is a negative number " << endl;
        }
            return 0;
    }

解决方案

This a good example of "Algorithm First, Coding Second".
The strategy here is "Divide and Conquer" - First find out the positiveness and evenness of the input SEPARATELY, then make the decision based on the combination of these findings.
Use this pseudo code as a guide:

GET input
SET isEven = 0 // default to odd
SET isPositive = 0  // default to neutral

// Determine positiveness
IF (input > 0) THEN
    SET isPositive = 1  // is positive
ELSE IF (input < 0) THEN
    SET isPositive = -1 // is negative

// Determine evenness
IF (input % 2 == 0) THEN
    SET isEven = 1 // is even

// Decision based on the combined finding of positiveness and evenness
IF (isPositive == 1 AND isEven == 1) THEN
   PRINT 'input is positive and even.'
// Figure out the rest yourself...
ELSE IF () THEN
// ...
ELSE
//...

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