测试数字是奇数还是偶数 [英] Test if number is odd or even

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问题描述

找出PHP中的数字/变量是奇数还是偶数的最简单,最基本的方法是什么? 与mod有关吗?

What is the simplest most basic way to find out if a number/variable is odd or even in PHP? Is it something to do with mod?

我已经尝试了一些脚本,但是.. google目前无法交付.

I've tried a few scripts but.. google isn't delivering at the moment.

推荐答案

您正确地认为mod是一个不错的起点.这是一个表达式,如果$number为偶数,则返回true,如果为奇数,则返回false:

You were right in thinking mod was a good place to start. Here is an expression which will return true if $number is even, false if odd:

$number % 2 == 0

适用于每个 integer PHP 值,另请参见算术运算符 PHP .

Works for every integerPHP value, see as well Arithmetic OperatorsPHP.

示例:

$number = 20;
if ($number % 2 == 0) {
  print "It's even";
}

输出:

甚至

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