分析从服务器的JSON文件 [英] parsing json file from server
本文介绍了分析从服务器的JSON文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我上传 JSON
文件到我的服务器。这是 JSON文件但是当我想分析它,它提供了以下错误:
错误解析数据org.json.JSONException:值小于,java.lang.String类型的DOCTYPE不能转换为JSONObject的!
我应该做的服务器,设置?我只设置 MIME
。
解决方案
例如响应:
<$p$p><$c$c>{"rows":[{"Fname":"rahim","Lname":"Durosimi","$p$pdictions":"4","C$p$pdictions":"3","Points":"15"},{"Fname":"Otunba","Lname":"Alagbe","$p$pdictions":"5","C$p$pdictions":"2","Points":"10"},{"Fname":"Olamide","Lname":"Jolaoso","$p$pdictions":"4","C$p$pdictions":"2","Points":"10"},{"Fname":"g","Lname":"ade","$p$pdictions":"1","C$p$pdictions":"1","Points":"5"},{"Fname":"Tiamiyu","Lname":"waliu","$p$pdictions":"1","C$p$pdictions":"1","Points":"5"}]}
相当于code您接收字符串的响应之后进行解析。
的JSONObject JSON =新的JSONObject的(内容);
JSONArray jArray = json.getJSONArray(行);
JSONObject的json_data = NULL;
的for(int i = 0; I&LT; jArray.length();我++){
json_data = jArray.getJSONObject(ⅰ);
字符串FNAME = json_data.getString(FNAME);
字符串LNAME = json_data.getString(L-NAME);
}
&LT; PHP
标题(内容类型:应用程序/ JSON);
$ CH = curl_init();
curl_setopt($ CH,CURLOPT_URL,您的网址在这里);
curl_setopt($沟道,CURLOPT_RETURNTRANSFER,1);
回声$输出= curl_exec($ CH);
curl_close($ CH);
?&GT;
I upload a json
file to my server. This is the json file but when I want to parse it, it gives the following error:
Error parsing data org.json.JSONException: Value <!DOCTYPE of type java.lang.String cannot be converted to JSONObject
which setting should I do in server? I only set MIME
.
You can review my codes here
解决方案
example response:
{"rows":[{"Fname":"rahim","Lname":"Durosimi","Predictions":"4","Cpredictions":"3","Points":"15"},{"Fname":"Otunba","Lname":"Alagbe","Predictions":"5","Cpredictions":"2","Points":"10"},{"Fname":"Olamide","Lname":"Jolaoso","Predictions":"4","Cpredictions":"2","Points":"10"},{"Fname":"g","Lname":"ade","Predictions":"1","Cpredictions":"1","Points":"5"},{"Fname":"Tiamiyu","Lname":"waliu","Predictions":"1","Cpredictions":"1","Points":"5"}]}
equivalent code to parse after you receive the response in string.
JSONObject json = new JSONObject(content);
JSONArray jArray = json.getJSONArray("rows");
JSONObject json_data = null;
for (int i = 0; i < jArray.length(); i++) {
json_data = jArray.getJSONObject(i);
String fname = json_data.getString("Fname");
String lname = json_data.getString("Lname");
}
<?php
header('Content-Type: application/json');
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "your url here");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
echo $output = curl_exec($ch);
curl_close($ch);
?>
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