链表的默认构造函数。 [英] Default constructor for a linked list.

问题描述

实现LinkedList类的默认构造函数。请记住，默认构造函数的工作是创建一个空列表。



在这个版本的Node中，我们使用一个struct with member int data和Node * next 。





我的下面的功能不正确。你能帮忙解决这个问题吗？



我尝试过的事情：

 LinkedList :: LinkedList（）
 {
 int data; 
 Node * next; 
 data = 0; 
 * next = NULL; 
 
} 

解决方案

可能它应该类似于

  class  LinkedList 
 {
  //  类的私有成员变量 
  int 数据; 
 Node * next; 
  //   ...  
  public ：
  //  构造函数：将对象置于已知状态 
 LinkedList（）：data（ 0 ），next（ nullptr ）{} 
  //   ...  
}; 

您好会员13041326 ，



此行错误：

 * next = NULL; 

应该是：

 next = NULL; 

next 是指向下一个节点的指针;你想在初始化（也就是构造函数）将它指向无（又名NULL）。



* next 将意味着存储在 next 的值。 next 是指针， * next 是节点 （ next 指向）。错误的行试图将0（NULL为0）分配给节点类型，这是错误的，因此这肯定会产生编译错误（例如，node = 0是不可能的）。

Implement the default constructor for the LinkedList class . Remember, the default constructor 's job is to create an empty list.

In this version of Node, we are using a struct with members int data and Node *next.


My function below is incorrect. Can you please help fix this?

What I have tried:

LinkedList::LinkedList()
{
   int data;
   Node *next;
   data=0;
   *next = NULL;
	
}

解决方案

Probably it should be something similar to

class LinkedList
{
  // private member variables of the class 
  int data;
  Node *next;
  //...
public:
  // constructor: put the object in a known state
  LinkedList() : data(0), next(nullptr) {}
  //...
};

Hi Member 13041326,

This line is wrong:

*next = NULL;

It should be:

next = NULL;

next is a pointer to the next node; you want to point it to none (aka NULL) at the initialization (aka constructor).

*next would mean the value stored at next. next is a pointer, and *next is the node (that next is pointing at). The erroneous line is trying to assign 0 (NULL is 0) to a node type which is wrong, hence this would definitely give a compile error (e.g. node = 0 is not possible).

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