如何创建一个XML API，这将使数据以我的Android应用程序 [英] how to create an xml api that will give data to my android app
问题描述
嗯，我有一个Android应用程序，需要与数据更新中... 我知道该怎么做在Android终端的XML解析... 但是当我试图通过follwing XML文件解析的数据（一）用我的应用程序的StringBuilder（二）我没有得到的数据...
well i have an android app that needs to be updated with data... i know what to do on android-end for xml parsing... but when i try to parse the data through the follwing xml file(a) using stringbuilder(b) i am not getting data in my app...
（一）data.xml中
(a)data.xml
<?xml version="1.0" encoding="utf-8"?>
<document version="first">
<stuff code="firststuff">
<item1 build="first">This is first item.</item1>
<item2 build="second">This is second item.</item2>
<item3 build="third">This is third item.</item3>
</stuff>
<stuff code="secondtstuff">
<item1 build="first">This is first item.</item1>
<item2 build="second">This is second item.</item2>
<item3 build="third">This is third item.</item3>
</stuff>
<stuff code="thirdstuff">
<item1 build="first">This is first item.</item1>
<item2 build="second">This is second item.</item2>
<item3 build="third">This is third item.</item3>
</stuff>
</document>
（二），我在我的Android应用程序中使用的字符串...
(b) string that i use in my android app...
http://www.xyz.com/data.xml?build=second
下面的3个文件（C）
Java的code主（四）HandlingXMLStuff（五）XMLDataCollected
java code below in 3 files (c)Main (d)HandlingXMLStuff (e)XMLDataCollected
（三）主要
package com.xyz.xmlpar1;
import java.net.URL;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.InputSource;
import org.xml.sax.XMLReader;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class Main extends Activity implements OnClickListener {
static final String BaseURL="http://www.xyz.com/data.xml?code=";
Button b;
TextView tv;
EditText et1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
et1=(EditText) findViewById(R.id.editText1);
b=(Button) findViewById(R.id.button1);
tv=(TextView) findViewById(R.id.textView1);
b.setOnClickListener(this);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
String item=et1.getText().toString();
StringBuilder URL=new StringBuilder(BaseURL);
URL.append(item);
String fullURL=URL.toString();
try{
URL website=new URL(fullURL);
SAXParserFactory spf=SAXParserFactory.newInstance();
SAXParser sp=spf.newSAXParser();
XMLReader xr=sp.getXMLReader();
HandlingXMLStuff doingWork=new HandlingXMLStuff();
xr.setContentHandler(doingWork);
xr.parse(new InputSource(website.openStream()));
String information=doingWork.getInformation();
tv.setText(information);
}catch(Exception e){
tv.setText("error");
}
}
}
（四）HandlingXMLStuff
(d)HandlingXMLStuff
package com.xyz.xmlpar1;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
public class HandlingXMLStuff extends DefaultHandler {
XMLDataCollected info=new XMLDataCollected();
public String getInformation(){
return info.datatoString();
}
@Override
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
// TODO Auto-generated method stub
if(localName.equals("code")){
String element=attributes.getValue("build");
info.setData(element);
}
}
}
（五）XMLDataCollected
(e)XMLDataCollected
package com.xyz.xmlpar1;
public class XMLDataCollected {
String datac=null;
public void setData(String c){
datac=c;
}
public String datatoString(){
return datac;
}
}
要获取第二的数据项。
我要去哪里错了???
where am i going wrong ???
推荐答案
您应该按照我贴在这里这个问题重复教程：<一href="http://stackoverflow.com/questions/14417475/parsed-xml-data-not-retrieving-in-android/14418003#14418003">Parsed XML数据未检索机器人
You should follow the tutorial that I posted on the duplicate of this question here: Parsed XML data not retrieving in android
虽然该教程并没有表现出越来越属性。
Although that tutorial does not show getting attributes.
总之，你的的startElement 应该是这个样子：
In short, your startElement should look something like this:
@Override
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
if(localName.equals("stuff")){
String element=attributes.getValue("code");
info.setData(element); //element will hold "firststuff" on the first execution
}
}
您将需要一个单独的如果为您要相互匹配的名字。
You will need a separate if for each name you are trying to match.
在通用的XML文件被称为像这样（用你的命名约定）：
Xml files in general are referred to like this (using your naming convention):
＆LT;的localName的attributeName =的AttributeValue＆GT; textValue＆LT; /的localName＆GT; 所以如果上述声明的意志处理行＆LT;东西code =firststuff＆GT; ＆LT; ...secondstuff＆GT; 等等，但你必须增加更多的处理的每个不同的的行。
<localName attributeName="attributeValue">textValue</localName> So the if statement above will handle the lines <stuff code="firststuff"> <..."secondstuff"> etc. but you will have to add more to handle each different line.
我强烈建议你按照教程获得这个成就，虽然，你一定会通过试验和错误中学到很多东西。
I strongly suggest you follow a tutorial to get this accomplished, although, you will definitely learn a lot through trial and error.
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