以下程序中的转换错误是什么？ [英] What is the conversion error coming in the following program ?

问题描述

以下程序借助指针将3D数组转换为1D数组。一些转换错误即将到来。错误发生的行包含赋值运算符，指向两侧指向int类型的指针。

The following program converts 3D array into 1D array with help of pointers . Some conversion error is coming . The line in which error is coming contains assignment operator with pointer to pointer to int type on both sides .

#include<iostream>
using namespace std ;
int main()
{
// REPLACING 3D ARRAY WITH A 2D ARRAY AND THEN INTO A 1D ARRAY USING               POINTERS  .  

int abc [2][2][3] ;
int **p[3][2] ;
int *c[6] ;
//          // abc gives address of first element of 3d array ie first 2d   array .

// abc is pointer to pointer to pointer to int type .

int i , j ;     // * abc represents address of first 1d array of first 2d array .

for (i=0 ; i<=2 ; i++) // *abc +1:address of second 1d array of first 2d 
{                            // array .
for (j=0 ; j<=1 ; j++)
{
p[i][j] =  *(abc+i )  + j ; // Conversion error comes here , but WHY ?

} 
}                  

for (i=0 ; i<=5 ; i++) 
{
for (j=0 ; j<=1 ; j++ )     
{
c[i] = *p[i][j] ;     
}

}

// entering array elements .
for (i=0 ; i<=5 ; i++)
{
cin>>* c[i] ;   

}

// required array elements .
for (i=0 ;i<=5 ;i++)
{
cout<<*c[i]<<"    "; // 3d array elements are accessed using 1d array  
}                                                        // of pointers .
}

我的尝试：



我试过在dev c ++上运行这个程序，但显示以下错误：



[错误]无法转换'int（*）[3]分配中的'to'int **'

What I have tried:

I have tried to run this program on dev c++ but displays following error :

[Error] cannot convert 'int (*)[3]' to 'int**' in assignment

推荐答案

很明显，当你理解数组访问中的机制时。你的abc是一个三维整数数组。



有效代码是：

It is pretty obvious, when you would understand the mechanismins in array access. Your abc is an 3-dimensional array of integers.

valid code is:

int value =  abc[i][j][k] ;//get value with array access
int *pointer =  &(abc[i][j][k]);//get pointer

使用数组访问更容易，避免使用大指针arhitmetics

It is easier to work with the array access and avoid big pointer arhitmetics

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