任何帮助编写关于课程的程序都会受到赞赏，并且已经尝试了一段时间 [英] Any help writing this program about classes would be appreciated, been trying for awhile

问题描述

任何帮助撰写此计划的所有部分的人都将不胜感激。我完全迷失了需要做什么。



类Coord有两个x和y坐标属性。该课程有两个成员函数，如下所示。

Any help writing all the parts for this program would be greatly appreciated. I am completely lost as to what needs to be done.

A class Coord has two attributes of x and y coordinates. The class has two member functions as defined below.

 #include <cstdlib>
class Coord {
    private:
        int x, y;
    public:
        Coord (int i1, int i2) : x(i1), y(i2) {
    }
    friend Coord operator- (Coord const& c1, Coord const& c2) {
        return Coord(c1.x-c2.x, c1.y-c2.y);
    }
    Coord abs() {
        return Coord(std::abs(x),std::abs(y));
    }
    int getX() {return x};
    int getY() {return y};
};
/*Note int abs (int n); Returns the absolute value of parameter n*/
A base class GeoObj is for geometric objects.
class GeoObj {
public:
// return center of gravity of geometric object.
virtual Coord center_of_gravity() const ;
//...
private:
Coord center; // center_of_gravity;
};

a）几何类Circle和类Line是从GeoObj派生的。定义并提供类Circle类和Line [10 Marks]的实现。定义并提供名为distance的函数模板的实现，该函数模板处理GeoObj [10 Marks]的两个对象之间的重心距离。计算应该使用运算符 - 用于两个对象的重心。这个距离函数的用法如下所示：

a) A geometric class Circle and class Line is derived from GeoObj. Define and provide implementation of class Circle class and Line [10 Marks]. Define and provide implementation of a function template called distance that processes the distance of center of gravity between two objects of GeoObj [10 Marks]. The calculation is supposed to use the operator – for the center of gravity of two objects. The usage of this distance function is shown below.

int main()
{
    Line l;
    Circle c, c1, c2;
    Coord d1 = distance(c1,c2);
    Coord d2 = distance(l,c);
}

b）定义并提供运算符的实现<<输出类型和center_of_gravity。例如，对于Circle对象，运算符<<输出Circle类型，后跟center_of_gravity的X和Y坐标。同样，对于Line对象，运算符<<输出Line，后跟center_of_gravity的X和Y坐标。您需要确定此运算符的位置（例如，类GeoObj，类Circle或类Line）<<应该定义。此操作符允许输出到标准显示，如控制台或文件。



c）定义一个驱动程序来测试类Circle，Line，function template distance和operator< ;< cout和文件流重载。



我尝试过：



我一直无法想出任何东西。我一直试图理解这个问题大约一周。

b) Define and provide implementation of operator << that outputs the type and center_of_gravity. For example, for a Circle object, the operator << outputs the type "Circle" followed by the X and Y coordinate of center_of_gravity. Likewise, for a Line object, the operator << outputs "Line" followed by the X and Y coordinate of center_of_gravity. You need to decide where (e.g. class GeoObj, class Circle or class Line) this operator << should be defined. This operator allows outputs to standard display such as the console or to a file.

c) Define a driver to test the class Circle, Line, function template distance and operator << overloaded for both cout and file streams.

What I have tried:

I have been unable to come up with anything. I have been trying to understand this problem for around a week.

推荐答案

Quote：

我一直无法想出任何东西。我一直试图了解这个问题大约一周

I have been unable to come up with anything. I have been trying to understand this problem for around a week

为了完成你的作业，你需要了解

• center-of-mass是 [ ^ ]（请注意，找到一个圆或一条线的质心是一项非常简单的任务。）
• 如何编写派生类（有许多教程免费提供。）
• 如何定义函数模板（再次， Google 是你的朋友）。
• 如何在C ++中重载运算符（例如，operator overloading - cppreference.com [ ^ ]）。


In order to complete your homework you need to understand

• what the center-of-mass is[^] (please note, locating the center-of-mass of a circle or a line is really a trivial task).
• How to write a derived class (there are many many tutorials freely available).
• How to define a function template (again, Google is you friend).
• How to overload operators in C++ (see, for instance "operator overloading - cppreference.com"[^]).




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