如何通过日期时间获取任务之间的时间 [英] How Do I Get The Time Between To Task By Datetime

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本文介绍了如何通过日期时间获取任务之间的时间的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

您好,我有多个任务分配给销售人员。任务按顺序依次流动。销售经理关注这项任务。



Hello, i have number of tasks assigned to sales person.the task is flow in sequence one after another. the sales manager have watch on that task.

EmpId OrderId   TaskName           TaskAssignedDate 
1        1      TakeOrder          11 Nov 2015 10:05:07
2        1      ProcessOrder       11 Nov 2015 10:07:07
3        1      PackOrder          12 Nov 2015 11:44:07
4        1      CourierOrder       13 Nov 2015 13:15:07
5        1      DeliverOrder       14 Nov 2015 15:32:07







这是我桌上的记录......我怎么能得到时间在任何两个任务之间。

说从TakeOrder到CourierOrder或PackOrder到DeliverOrder




this are the records in my table ... how can i get the time between any two tasks.
say from TakeOrder to CourierOrder OR PackOrder to DeliverOrder

推荐答案

DECLARE @TakeOrder DATETIME;
DECLARE @ProcessOrder  DATETIME;
 
-- Time of the ARTICLE created
SET @TakeOrder = '11 Nov 2015 10:05:07';
 
-- Simulation of NOW datetime
-- (in real world you would probably use GETDATE())
SET @ProcessOrder  = '11 Nov 2015 10:07:07';
 
-- Created 9 days ago.
SELECT 'Diff ' + CAST(DATEDIFF(day, @TakeOrder, @ProcessOrder ) AS NVARCHAR(50)) + ' days ago.' as diff_by_day;
 
-- Created 1 weeks, 2 days, 3 hours, 25 minutes and 20 seconds ago.
SELECT 'Diff '
    + CAST(DATEDIFF(second, @TakeOrder, @ProcessOrder ) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
    + CAST(DATEDIFF(second, @TakeOrder, @ProcessOrder ) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
    + CAST(DATEDIFF(second, @TakeOrder, @ProcessOrder ) / 60 / 60 % 24  AS NVARCHAR(50)) + ' hours, '
    + CAST(DATEDIFF(second, @TakeOrder, @ProcessOrder ) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
    + CAST(DATEDIFF(second, @TakeOrder, @ProcessOrder ) % 60 AS NVARCHAR(50)) + ' seconds ago.' as Difference_by_hole;


试试吧使用DATEDIFF(datepart,startdate,enddate)函数。
Try it by using DATEDIFF(datepart,startdate,enddate) function.


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