如何在python中获得两个日期的差异？ [英] How can I get a difference of two dates in python ?

问题描述

您好我有与python相关的查询。我希望得到2个不同时间的时间差。其中一次，我作为字符串获得（作为手动输入）

第二次是当地时间。

以下是源代码：

Hello I have query related to python. I want to get difference of time span of 2 different times. One of the time, which I obtain as string (As a manual input)
second time is local time.
Here is source code below :

from time import strptime
from time import localtime
from datetime import date
from datetime import datetime

out="20150827173103"
time1=datetime(time.strptime(out,"%Y%m%d%H%M%S"))
print(time1)           #string converted into time format#

time2=time.strftime("%Y%m%d%H%M%S")
print(time2)           #got local time in string format#

time3=datetime(time.strptime(time2,"%Y%m%d%H%M%S")    #local time in string is converted into time format#
diff=time3-time1
print(diff)

错误：ValueError：（'年必须在1..9999'，（2015年，8,27,17,31,3,3,239，-1））在第6行。

请建议我如何才能得到这个问题的解决方案。

Error: ValueError: ('year must be in 1..9999', (2015, 8, 27, 17, 31, 3, 3, 239, -1)) at 6th line.
Please suggest how can I get the solution of this problem.

推荐答案

previous=date(2015,8,27)
current=date.today()
difference=current - previous
print(difference)

类似的代码代码

Similar code for times

t1=datetime.strptime("20150827130100", "%Y%m%d%H%M%S")
t2=datetime.today()
tdiff=t2-t1
tdiff

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