如何根据文件内容过滤OpenFileDialog中的文件？ [英] How do I filter files in an OpenFileDialog based on the contents of the file ?

问题描述

我是C＃和.Net框架的新手，想知道我是否可以就这一特定主题提出一些建议，



我的要求是，我需要为我的应用程序使用OpenFileDialog，但其行为略有不同。我有自定义扩展名为* .sda的文件，这些sda文件也有与之关联的版本。版本是文件的前4个字节。但是，不考虑版本号，它们都具有相同的扩展名sda。



如果我使用sda扩展名过滤文件，OpenFileDialog会显示所有SDA文件。我想改变它的行为，它读取SDA文件的版本号，并只显示特定版本的SDA文件。因此，这是一个基于内容而不是扩展名来过滤文件的问题。



如何实现这一目标？任何想法都表示赞赏。

请原谅我可怜的英语....

Hi, I am quite new to C# and the .Net framework and was wondering if I can get some advise on this particular topic,

My requirement is that, I need to have an OpenFileDialog for my application, but with a slight difference in its behavior. I have files with a custom extension as *.sda, also these sda files have versions associated with them. The versions are the first 4 bytes of the files. However, without regard to the version number they all have the same extension sda.

If I filter the files with sda extension, OpenFileDialog shows all SDA files. I would like to alter its behavior where it reads the version number of the SDA files and displays only a particular versioned SDA files. Thus, it is a question of filtering files based on their content and not on their extension.

How about achieving this ? Any ideas are appreciated.
Pardon my poor English....

推荐答案

我很确定这不能做到。 OpenFileDialogue在文件过滤器方面非常简单。



您必须进行自定义对话才能执行目录文件搜索。您可以使它非常基本，因为您不需要OpenFileDialogue为您提供的所有额外功能。

I'm pretty sure that this cannot be done. The OpenFileDialogue is very set-in-its-ways when it comes to file filters.

You will have to make a custom dialogue that performs the directory file search for you. You can make it pretty basic as you won't need all the extra functionality that the OpenFileDialogue presents you with.

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