这个C程序使用函数有什么问题？ [英] What is wrong with this C program using function?

问题描述

//To find the power of a number
#include<stdio.h>
#include<conio.h>
int power(int a,int b);
int main()
{	clrscr();
	int a,b;
	printf("\nEnter the base:");
	scanf("%d",&a);
	printf("\nEnter the power:");
	scanf("%d",&b);
	printf("\nThe answer is:%d",power(a,b));
	getch();
	return 0;
}
int power(int x,int y)
{       int c;
	for(int i=1;i<=y;i++)
	c*=x;
	return c;
}

当我输入基数和指数时，我得到了一个无法回答的答案。例如，当我输入2表示基数而3表示指数时，而不是获得8，我得到一个数字很多的数字。请帮我。谢谢。

When I enter the base and exponent, I get an irrevelant answer. For example, when I type 2 for base and 3 for exponent, instead of getting 8, I get a number with many digits. Please help me. Thanks.

推荐答案

在C / C ++中，未初始化的变量具有未定义的值...原因是用于存储变量的内存块（变量名称）实际上是一个指向内存地址的指针）过去可能已被其他变量使用并且从未清理过......

因此，如果变量的初始值很重要（就像在你的情况下那样）你有进行初始化...

在Microsoft编译器中将警告级别设置为4将提醒您可能未初始化的变量...

在GCC中，您可以使用 -Wyybe -ininitialized 做同样的事情......

In C/C++ a variable that not initialized has undefined value...The reason is that the memory block used to store the variable (the variable name is actually a pointer to a memory address) may had used in the past by other variables and never cleaned...
So if the initial value of a variable is important (like in your case) you have to do that initialization...
In Microsoft compilers setting warning level to 4 will alert you about potentially uninitialized variables...
In GCC you may use -Wmaybe-uninitialized to do the same...

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