如何消除错误“赋值中不兼容的类型”第17行 [英] how to eliminate error "incompatible types in assignment" line 17

问题描述

  / *  该程序的目的是拆分e中的内容我]并将它们添加到数组名称，姓氏和分数。 * /  
 
  int  main（）
 {
  int 条目，i，选项; 
 printf（  \ n请指出您要输入的记录数：\ n）; 
 scanf（ ％d，& entry）; 
  char  ent [entry] [ 100 ]，name [entry] [ 20 ]，姓[entry] [ 20 ]，得分[entry] [ 10 ]; 
 printf（  \ n请输入学生的记录（在每条记录后输入一个新行），如下格式名字姓氏得分\ n）; 
 
  for （i =  0 ; i< entry + 1; i ++） 
 {
得到（ent [i]）; 
 printf（ ％s，ent [i]）; 
} 
 
  for （i =  0 ; i< entry +1; i ++）
 {
 name [i] = strtok（ent [i]， ）; <  - 错误
 printf（  \ n％s \ n，名称[一世]）; 
} 
 
 printf（  \ n请选择合适的选项：< /跨度>）; 
 printf（  \ n打印记录（按1）\ n按名字搜索（按2） \\ n按姓氏搜索（按3）\ n按分数排序（按4）\ n按姓氏排序（按5）\ n退出程序（按0）\ n）; 
 scanf（ ％d，& option）; 
  return   0 ; 
} 

解决方案

  //  您的for循环显示不正确 
  //  数组基于零，因此范围为0至entry-1  
 
  for （i =  0 ; i< entry; >  {
得到（ent [i]）; 
 printf（ ％s，ent [i]）; 
} 
 
  for （i =  0 ; i< entry; >  {
 name [i] = strtok（ent [i]， ）; 
 printf（  \ n％s \ n，name [i]）; 
} 

/* The aim of the program is to split the contents in e[i] and add them to the arrays name , surname and score. */

int main()
{
    int entry,i,option;
    printf("\nPlease indicate the number of records you want to enter :\n");
    scanf("%d",&entry);
    char ent[entry][100],name[entry][20],surname[entry][20],score[entry][10];
    printf("\nPlease input records of students (enter a new line after each record), with following format first name last name score \n");

    for (i=0; i<entry+1; i++)
    {
        gets(ent[i]);
        printf("%s",ent[i]);
    }

    for(i=0; i<entry+1; i++)
    {
        name[i] = strtok(ent[i]," ");   <- Error
        printf("\n%s\n",name[i]);
    }

    printf("\nPlease choose the appropriate options :");
    printf("\nPrint records (press 1)\nSearch by first name (press 2)\nSearch by last name (press 3)\nSort by score (press 4)\nSort by last name (press 5)\nExit the program (press 0)\n");
    scanf("%d",&option);
    return 0;
}

解决方案

//Your for loops appear to be incorrect
//Arrays are zero based, so the range is 0 to entry-1 

    for (i=0; i<entry;>    {
        gets(ent[i]);
        printf("%s",ent[i]);
    }
 
    for(i=0; i<entry;>    {
        name[i] = strtok(ent[i]," ");  
        printf("\n%s\n",name[i]);
    }

这篇关于如何消除错误“赋值中不兼容的类型”第17行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！