如何使用Php搜索和回显特定部分？ [英] How to Search and echo Specific Part Using Php ?
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问题描述
我想要php代码搜索一段我在变量中提供的代码，然后从代码起点回复大约40个单词的文字。
例如，我的代码存储在一个变量中：
< html xmlns = http://www.w3.org/1999/xhtml >
< head > < meta charset = utf-8 / > < title >
Dotcabs
< / title > < meta 名称 = viewport 内容 = width =设备宽度，高度=设备高度 / > < link rel = stylesheet href = css / style.css / > < link rel = stylesheet href = css / responsive.css / >
< script src = js / jquery-1.11 .1.js > < / script >
< script src = js / script.js > < ; / script >
<！ -
< script src =https://maps.google.com/地图/ API / JS传感器=假>？< /脚本>
- >
< script src = https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=places&sensor=false > < / script >
< script src = js / places-search-box.js > < / script >
< link rel = stylesheet href = http：// code .jquery.com / ui / 1.10.4 / themes / smoothness / jquery-ui.css / >
< 脚本 src = http://code.jquery.com/ui/1.10.4/jquery-ui.js > < / script >
< script < span class =code-attribute> src = js / jquery-ui-timepicker-addon。 js > < / script >
我想找到字代码.jquery然后回显匹配术语中的前30个或更多单词，
在这种情况下，我需要搜索code.jquery，它现在在代码中所以现在，我想回复50或我选择的任何字符：
code.jquery.com/ui/1.10.4/jquery-ui.js
感谢任何帮助！
解决方案
尝试通过阅读这两个函数来自己：
1.使用 strstr [ ^ ]找到第一次出现的字符串。
2.然后，使用 substr [ ^ ]至从＃1返回字符串的一部分。
还有更多字符串函数 [ ^ ]可以满足您的各种需求
Hi , I want php code to search a piece of code which i made it available in an variable , and then echo around 40 words of text from the code starting point .
For Example , My code is stored in an variable as :
<html xmlns="http://www.w3.org/1999/xhtml">
<head><meta charset="utf-8" /><title>
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</title><meta name="viewport" content="width=device-width, height=device-height" /><link rel="stylesheet" href="css/style.css" /><link rel="stylesheet" href="css/responsive.css" />
<script src="js/jquery-1.11.1.js"></script>
<script src="js/script.js"></script>
<!--
<script src="https://maps.google.com/maps/api/js?sensor=false"></script>
-->
<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=places&sensor=false"></script>
<script src="js/places-search-box.js"></script>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css" />
<script src="http://code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
<script src="js/jquery-ui-timepicker-addon.js"></script>
I want to find the word code.jquery and then echo the first 30 or More words from the matched term ,
Here in case, I need to search code.jquery , Its present in code so now , I want to echo this upto 50 or any characters of my choice:
code.jquery.com/ui/1.10.4/jquery-ui.js
Any help is appreciated !
解决方案
Try it yourself by reading up on these 2 functions:
1. Use strstr[^] to find the first occurrence of a string.
2. then, use substr[^] to return part of a string from #1.
There are more string functions[^] that you can use for your varied needs.
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