如何使用php回显图片? [英] How to echo picture using php?

问题描述

请帮我处理这些家伙，我有这个代码:

Please help me with this guys, I have this code:

if(move_uploaded_file($_FILES['userfile']['tmp_name'],"C:/xampp/htdocs/new/admin/gallery/{$_FILES['userfile']['name']}")
{
    echo '<center><img src="admin/gallery/{$_FILES['userfile']['name']}" width="100" height="100"/>'.'</center>';     
    // echo "success!:)";
} 
else 
{
    echo "photo not uploaded";
}

这里的问题是当我回显它并使用它的 tmpname 时，我在本节中出错

the problem here is when i echo it and use its tmpname i am having an error in this section

<img src="admin/gallery/{$_FILES['userfile']['name']}" width="100" //....

用户文件以红色下划线标出.使用它的临时名称来回应它是错误的吗?请帮帮我...

the userfile is underlined in red. Is it wrong to use its tempname in echoing it? help me please...

推荐答案

像这样改变你的 echo 语句，

Change your echo statement like this,

echo '<center><img src="admin/gallery/'.{$_FILES['userfile']['name']}.'" width="100" height="100"/>'.'</center>';

还有你的 if 检查显示不正确.

Also your if checks showing incorrectly.

可能是这样的，

if(move_uploaded_file($_FILES['userfile']['tmp_name'],"C:/xampp/htdocs/new/admin/gallery/{$_FILES['userfile']['name']")
{
 .....
}

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